What is the integral of sqrt(x)(14x^2+x) ?

The integral of sqrt(x)(14x^2+x) is 4x^{7/2}+2/5 x^{5/2}+C

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integral of sqrt(x)(14x^2+x)

\int x (14 x^{2} + x) d x

4 x^{\frac{7}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

Solution steps

\int x (14 x^{2} + x) d x

Expand

x (14 x^{2} + x) : 14 x^{\frac{5}{2}} + x^{\frac{3}{2}}

= \int 14 x^{\frac{5}{2}} + x^{\frac{3}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 14 x^{\frac{5}{2}} d x + \int x^{\frac{3}{2}} d x

\int 14 x^{\frac{5}{2}} d x = 4 x^{\frac{7}{2}}

\int x^{\frac{3}{2}} d x = \frac{2}{5} x^{\frac{5}{2}}

= 4 x^{\frac{7}{2}} + \frac{2}{5} x^{\frac{5}{2}}

Add a constant to the solution

= 4 x^{\frac{7}{2}} + \frac{2}{5} x^{\frac{5}{2}} + C

What is the integral of sqrt(x)(14x^2+x) ?
The integral of sqrt(x)(14x^2+x) is 4x^{7/2}+2/5 x^{5/2}+C