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Popular Calculus >

integral of (1/x-1)

Solution

\int (\frac{1}{x} - 1) d x

Solution

ln ∣ x ∣ - x + C

Solution steps

\int \frac{1}{x} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x - \int 1 d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int 1 d x = x

= ln ∣ x ∣ - x

Add a constant to the solution

= ln ∣ x ∣ - x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (1/x-1) ?
The integral of (1/x-1) is ln|x|-x+C