y^'=(y-1)^2,y(0)=0

Lösung

y^{^{'}} = (y - 1)^{2}, y (0) = 0

y = \frac{t}{t + 1}

Schritte zur Lösung

y^{'} (t) = (y - 1)^{2}

Solve separable ODE:

y = \frac{t}{t + 1}

y = \frac{t}{t + 1}

(e^{x} \cdot e^{- x}) \frac{d y}{d x} = y^{2}

y^{^{'}} + n^{2} y - y = a

\frac{d y}{d t} = - 0.4 y + 28

(x - 2) y^{^{'}} - y + 1 = 0

a y^{^{'}} = - b y^{2} - c, y (0) = 10