What is the integral of ((x+5))/((x^2+16)) ?

The integral of ((x+5))/((x^2+16)) is 1/2 ln|x^2+16|+5/4 arctan(x/4)+C

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integral of ((x+5))/((x^2+16))

\int \frac{( x + 5 )}{( x ^{2} + 16 )} d x

\frac{1}{2} ln x^{2} + 16 + \frac{5}{4} arctan (\frac{x}{4}) + C

Solution steps

\int \frac{x + 5}{x ^{2} + 16} d x

Expand

\frac{x + 5}{x ^{2} + 16} : \frac{x}{x ^{2} + 16} + \frac{5}{x ^{2} + 16}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{x ^{2} + 16} d x + \int \frac{5}{x ^{2} + 16} d x

\int \frac{x}{x ^{2} + 16} d x = \frac{1}{2} ln x^{2} + 16

\int \frac{5}{x ^{2} + 16} d x = \frac{5}{4} arctan (\frac{x}{4})

= \frac{1}{2} ln x^{2} + 16 + \frac{5}{4} arctan (\frac{x}{4})

Add a constant to the solution

= \frac{1}{2} ln x^{2} + 16 + \frac{5}{4} arctan (\frac{x}{4}) + C

What is the integral of ((x+5))/((x^2+16)) ?
The integral of ((x+5))/((x^2+16)) is 1/2 ln|x^2+16|+5/4 arctan(x/4)+C