y^'=(e^{-x})/(sin(y)),y(0)=1

Lösung

y^{^{'}} = \frac{e ^{- x}}{sin ( y )}, y (0) = 1

y = arccos (e^{- x} + cos (1) - 1) + 2 πn, y = - arccos (e^{- x} + cos (1) - 1) + 2 πn

Schritte zur Lösung

y^{'} (x) = \frac{e ^{- x}}{sin ( y )}

Solve separable ODE:

y = arccos (e^{- x} + cos (1) - 1) + 2 πn, y = - arccos (e^{- x} + cos (1) - 1) + 2 πn

y = arccos (e^{- x} + cos (1) - 1) + 2 πn, y = - arccos (e^{- x} + cos (1) - 1) + 2 πn

\frac{d y}{d x} = \frac{x ( y - 1 )}{( y - 2 ) ( x ^{2} + 1 )}

y^{^{'}} = x^{2} y^{- 3}, y (0) = 4

y^{^{'}} + 8 y = 32

\frac{d v}{d t} = 90 - \frac{4}{100} v

x^{^{'}} = 6 x + 7