2x^{''}+x=3t^2+10t

Lösung

2 x^{^{''}} + x = 3 t^{2} + 10 t

x = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2}) + 3 t^{2} + 10 t - 12

Schritte zur Lösung

2 x^{''} (t) + x = 3 t^{2} + 10 t

Solve linear ODE:

x = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2}) + 3 t^{2} + 10 t - 12

x = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2}) + 3 t^{2} + 10 t - 12

y^{^{''}} + y^{^{'}} - y = 1

y^{^{''}} + 4 y = 16 x cos (2 x)

y^{^{''}} + 36 y = sin (9 x)

y^{^{''}} + y = sec (2 x)

- 2 y^{^{''}} + 18 y + 2 (3 x^{2} + x + \frac{10}{3}) = 0