y^{''}+y=sec(2x)

Lösung

y^{^{''}} + y = sec (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{2}{4} cos (x) (ln (2 cos (x) + 1) - ln (2 cos (x) - 1)) + sin (x) \cdot \int cos (x) sec (2 x) d x

Schritte zur Lösung

y^{''} (x) + y = sec (2 x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{2}{4} cos (x) (ln (2 cos (x) + 1) - ln (2 cos (x) - 1)) + sin (x) \cdot \int cos (x) sec (2 x) d x

y = c_{1} cos (x) + c_{2} sin (x) - \frac{2}{4} cos (x) (ln (2 cos (x) + 1) - ln (2 cos (x) - 1)) + sin (x) \cdot \int cos (x) sec (2 x) d x

- 2 y^{^{''}} + 18 y + 2 (3 x^{2} + x + \frac{10}{3}) = 0

D C = 1.5226 D U S

y^{^{''}} - 4 y^{^{'}} + 5 y = 4 e^{- x}

y^{^{''}} - y^{^{'}} - 2 y = - 2 x + 4 x^{2}

y^{^{''}} - y = 2 e^{x} + 6 e^{2 x}