de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

y^{''}-2y^'+2y=x+1,y(0)=3,y^'(0)=0

Lösung

y^{^{''}} - 2 y^{^{'}} + 2 y = x + 1, y (0) = 3, y^{^{'}} (0) = 0

Lösung

y = e^{x} (2 cos (x) - \frac{5}{2} sin (x)) + \frac{x}{2} + 1

Schritte zur Lösung

y^{''} (x) - 2 y^{'} (x) + 2 y = x + 1

Solve linear ODE:

y = e^{x} (2 cos (x) - \frac{5}{2} sin (x)) + \frac{x}{2} + 1

y = e^{x} (2 cos (x) - \frac{5}{2} sin (x)) + \frac{x}{2} + 1

Graph

Beliebte Beispiele

y^{''}-2y^'+2y=e^x 1/(sin(x))

y^{^{''}} - 2 y^{^{'}} + 2 y = e^{x} \frac{1}{sin ( x )}

y^{''}+y^'-2y=2e^{-2x}

y^{^{''}} + y^{^{'}} - 2 y = 2 e^{- 2 x}

(d^2x)/(dt^2)+36x=10sin(4t),x(0)=0

\frac{d ^{2} x}{d t ^{2}} + 36 x = 10 sin (4 t), x (0) = 0

y^{''}-3y^'=3e^{3t}

y^{^{''}} - 3 y^{^{'}} = 3 e^{3 t}

y^{''}-10y^'+24y=48x^2+10

y^{^{''}} - 10 y^{^{'}} + 24 y = 48 x^{2} + 10