What is the solution for xyy^'-y^2=x^4 ?

The solution for xyy^'-y^2=x^4 is y=xsqrt(x^2+c_{1)},y=-xsqrt(x^2+c_{1)}

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xyy^'-y^2=x^4

x y y^{^{'}} - y^{2} = x^{4}

y = x x^{2} + c_{1}, y = - x x^{2} + c_{1}

Solution steps

x y y^{'} (x) - y^{2} = x^{4}

Solve Bernoulli ODE:

y = x x^{2} + c_{1}, y = - x x^{2} + c_{1}

y = x x^{2} + c_{1}, y = - x x^{2} + c_{1}

What is the solution for xyy^'-y^2=x^4 ?
The solution for xyy^'-y^2=x^4 is y=xsqrt(x^2+c_{1)},y=-xsqrt(x^2+c_{1)}