What is the sum from n=1 to infinity of-1/(n^2) ?

The sum from n=1 to infinity of-1/(n^2) is converges

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sum from n=1 to infinity of-1/(n^2)

n = 1 \sum \infty - \frac{1}{n ^{2}}

converges

Solution steps

n = 1 \sum \infty - \frac{1}{n ^{2}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= - n = 1 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= - converges

= converges

What is the sum from n=1 to infinity of-1/(n^2) ?
The sum from n=1 to infinity of-1/(n^2) is converges