What is the integral from 0 to 1 of \sqrt[3]{x}-x^3 ?

The integral from 0 to 1 of \sqrt[3]{x}-x^3 is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 1 of \sqrt[3]{x}-x^3

\frac{1}{2}

Decimal

0.5

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

= \frac{3}{4} - \frac{1}{4}

Simplify

\frac{3}{4} - \frac{1}{4} : \frac{1}{2}

= \frac{1}{2}

What is the integral from 0 to 1 of \sqrt[3]{x}-x^3 ?
The integral from 0 to 1 of \sqrt[3]{x}-x^3 is 1/2