What is the tangent of f(x)=5x-9x^2,\at x=1 ?

The tangent of f(x)=5x-9x^2,\at x=1 is y=-13x+9

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tangent of f(x)=5x-9x^2,\at x=1

tangent of

f (x) = 5 x - 9 x^{2}, at x = 1

y = - 13 x + 9

Solution steps

Find the tangent point:

(1, - 4)

Find the slope of

f (x) = 5 x - 9 x^{2} : \frac{df ( x )}{d x} = 5 - 18 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 13

Find the line with slope m=

- 13

and passing through

(1, - 4) : y = - 13 x + 9

y = - 13 x + 9

What is the tangent of f(x)=5x-9x^2,\at x=1 ?
The tangent of f(x)=5x-9x^2,\at x=1 is y=-13x+9