What is the tangent of f(x)=(5x-7)/(x+1),\at x=0 ?

The tangent of f(x)=(5x-7)/(x+1),\at x=0 is y=12x-7

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tangent of f(x)=(5x-7)/(x+1),\at x=0

tangent of

f (x) = \frac{5 x - 7}{x + 1}, at x = 0

y = 12 x - 7

Solution steps

Find the tangent point:

(0, - 7)

Find the slope of

f (x) = \frac{5 x - 7}{x + 1} : \frac{df ( x )}{d x} = \frac{12}{( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(0, - 7) : y = 12 x - 7

y = 12 x - 7

What is the tangent of f(x)=(5x-7)/(x+1),\at x=0 ?
The tangent of f(x)=(5x-7)/(x+1),\at x=0 is y=12x-7