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Beliebt Rechnen >

integral of 8x^3e^{4x}

Lösung

\int 8 x^{3} e^{4 x} d x

Lösung

\frac{1}{32} (64 e^{4 x} x^{3} - 3 (16 e^{4 x} x^{2} - 2 (4 e^{4 x} x - e^{4 x}))) + C

Schritte zur Lösung

\int 8 x^{3} e^{4 x} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int x^{3} e^{4 x} d x

Wende U-Substitution an

= 8 \cdot \int \frac{e ^{u} u ^{3}}{256} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \frac{1}{256} \cdot \int e^{u} u^{3} d u

Wende die partielle Integration an

= 8 \cdot \frac{1}{256} (u^{3} e^{u} - \int 3 u^{2} e^{u} d u)

\int 3 u^{2} e^{u} d u = 3 (u^{2} e^{u} - 2 (e^{u} u - e^{u}))

= 8 \cdot \frac{1}{256} (u^{3} e^{u} - 3 (u^{2} e^{u} - 2 (e^{u} u - e^{u})))

Setze in

u = 4 x

ein

= 8 \cdot \frac{1}{256} ((4 x)^{3} e^{4 x} - 3 ((4 x)^{2} e^{4 x} - 2 (e^{4 x} \cdot 4 x - e^{4 x})))

Vereinfache

8 \cdot \frac{1}{256} ((4 x)^{3} e^{4 x} - 3 ((4 x)^{2} e^{4 x} - 2 (e^{4 x} \cdot 4 x - e^{4 x}))) : \frac{1}{32} (64 e^{4 x} x^{3} - 3 (16 e^{4 x} x^{2} - 2 (4 e^{4 x} x - e^{4 x})))

= \frac{1}{32} (64 e^{4 x} x^{3} - 3 (16 e^{4 x} x^{2} - 2 (4 e^{4 x} x - e^{4 x})))

Füge eine Konstante zur Lösung hinzu

= \frac{1}{32} (64 e^{4 x} x^{3} - 3 (16 e^{4 x} x^{2} - 2 (4 e^{4 x} x - e^{4 x}))) + C

Graph

Beliebte Beispiele

tangent f(x)=-8x^2-7x,\at x=-4

t an g e n t f (x) = - 8 x^{2} - 7 x, at x = - 4

integral of (x^2-3x+12)/((x^2-4x+11)^2)

\int \frac{x ^{2} - 3 x + 12}{( x ^{2} - 4 x + 11 ) ^{2}} d x

derivative of 1/(x^3-2/(x^2))

\frac{d}{d x} (\frac{1}{x ^{3}} - \frac{2}{x ^{2}})

derivative (x^4+7x^2-3)^4

d er i v a t i v e (x^{4} + 7 x^{2} - 3)^{4}

tangent f(x)= 5/(x^2),\at x=1

t an g e n t f (x) = \frac{5}{x ^{2}}, at x = 1