extreme (x^2)/((x-5)^2)

Lösung

extrempunkte

\frac{x ^{2}}{( x - 5 ) ^{2}}

Minimum (0, 0)

Schritte zur Lösung

f^{'} (x) = - \frac{10 x}{( x - 5 ) ^{3}}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < 5,

Absteigend

: 5 < x < \infty

Stecke

x = 0

\frac{x ^{2}}{( x - 5 ) ^{2}} : 0

Minimum (0, 0)

e x t re m e f (x) = 6 x - 12 cos (x), - 2 \leq x \leq 0

e x t re m e f (x) = 2 x^{3} - 33 x^{2} + 144 x + 3

e x t re m e f (x) = \frac{( 2 x ^{3} + 5 x )}{( x + 7 )}

e x t re m e f (x) = 2 x^{3} - 15 x^{2} + 6

e x t re m e (x - 7) e^{x}