extreme 2x^3+3x^2-12x-18

Lösung

extrempunkte

2 x^{3} + 3 x^{2} - 12 x - 18

Maximum (- 2, 2), Minimum (1, - 25)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} + 6 x - 12

Intervalle finden:

Ansteigend

: - \infty < x < - 2,

Absteigend

: - 2 < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - 2

2 x^{3} + 3 x^{2} - 12 x - 18 : 2

Maximum (- 2, 2)

Stecke

x = 1

2 x^{3} + 3 x^{2} - 12 x - 18 : - 25

Minimum (1, - 25)

Maximum (- 2, 2), Minimum (1, - 25)

e x t re m e f (x) = 4.5 x^{2} - 7.1 x + 3.9

e x t re m e x^{3} - 9 x^{2} + 24 x - 12

e x t re m e 9 - x^{2}, - 3 \leq x \leq 2

e x t re m e f (x) = \frac{x ^{6}}{10} - \frac{2 x ^{5}}{3}

e x t re m e f (x, y) = 2 x^{2} + 4 y x - x - 2 y