extreme f(x)=2x^2+3x-1

解答

极值点

f (x) = 2 x^{2} + 3 x - 1

极小值 (- \frac{3}{4}, - \frac{17}{8})

求解步骤

f^{'} (x) = 4 x + 3

Find intervals:

递减

: - \infty < x < - \frac{3}{4},

递增

: - \frac{3}{4} < x < \infty

将

x = - \frac{3}{4}

代入

2 x^{2} + 3 x - 1 : - \frac{17}{8}

极小值 (- \frac{3}{4}, - \frac{17}{8})

e x t re m e f (x) = ln (6 - ln (x))

e x t re m e 7 x^{4} - 4 x^{2} - 8 x - 5

e x t re m e 1 - (y + 1) 1 - y^{2} + y

e x t re m e f (x, y) = e^{x} - e^{x y}

e x t re m e f (x, y) = 2 x^{2} - 8 x y + 10 y^{2} + 10 x - 4 y - 5