2x^2-5y=20

Lösung

2 x^{2} - 5 y = 20

(h, k) = (0, - 4), p = \frac{5}{8}

Schritte zur Lösung

2 x^{2} - 5 y = 20

Rewrite

2 x^{2} - 5 y = 20

in the standard form:

4 \cdot \frac{5}{8} (y - (- 4)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 4), p = \frac{5}{8}