-x^2-6x+y-8=0

解答

- x^{2} - 6 x + y - 8 = 0

(h, k) = (- 3, - 1), p = \frac{1}{4}

求解步骤

- x^{2} - 6 x + y - 8 = 0

将

- x^{2} - 6 x + y - 8 = 0

改写为标准形式

4 \cdot \frac{1}{4} (y - (- 1)) = (x - (- 3))^{2}

因此抛物线性质是:

(h, k) = (- 3, - 1), p = \frac{1}{4}

x^{2} + y^{2} - 2 x + 4 y - 4 = 0

d i rec t r i x x = - \frac{1}{12} y^{2}

4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

v er t i ces x^{2}