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受欢迎的三角函数 >

sqrt(2)sec(x)+2=0

解答

2 sec (x) + 2 = 0

解答

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

+1

度数

x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n

求解步骤

2 sec (x) + 2 = 0

将

2

到右边

2 sec (x) + 2 = 0

两边减去

2

2 sec (x) + 2 - 2 = 0 - 2

化简

2 sec (x) = - 2

2 sec (x) = - 2

两边除以

2

2 sec (x) = - 2

两边除以

2

\frac{2 sec ( x )}{2} = \frac{- 2}{2}

化简

\frac{2 sec ( x )}{2} = \frac{- 2}{2}

化简

\frac{2 sec ( x )}{2} : sec (x)

\frac{2 sec ( x )}{2}

约分:

2

= sec (x)

化简

\frac{- 2}{2} : - 2

\frac{- 2}{2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2}{2}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{2}{2 ^{\frac{1}{2}}}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{2 ^{1}}{2 ^{\frac{1}{2}}} = 2^{1 - \frac{1}{2}}

= 2^{1 - \frac{1}{2}}

数字相减:

1 - \frac{1}{2} = \frac{1}{2}

= 2^{\frac{1}{2}}

使用根式运算法则:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= - 2

sec (x) = - 2

sec (x) = - 2

sec (x) = - 2

sec (x) = - 2

的通解

sec (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn

作图

流行的例子

6 sin (θ) - 3 = 0

cot^2(x)-csc(x)=1

cot^{2} (x) - csc (x) = 1

cos (2 x) = - 0.6

2sin(x)-cos(x)=0

2 sin (x) - cos (x) = 0

2cos(x)=sin(2x)

2 cos (x) = sin (2 x)