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受欢迎的三角函数 >

8sqrt(2)cos(θ)+6=-2

解答

82 cos (θ) + 6 = - 2

解答

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

+1

度数

θ = 13 5^{\circ} + 36 0^{\circ} n, θ = 22 5^{\circ} + 36 0^{\circ} n

求解步骤

82 cos (θ) + 6 = - 2

将

6

到右边

82 cos (θ) + 6 = - 2

两边减去

6

82 cos (θ) + 6 - 6 = - 2 - 6

化简

82 cos (θ) = - 8

82 cos (θ) = - 8

两边除以

82

82 cos (θ) = - 8

两边除以

82

\frac{8 2 cos ( θ )}{8 2} = \frac{- 8}{8 2}

化简

\frac{8 2 cos ( θ )}{8 2} = \frac{- 8}{8 2}

化简

\frac{8 2 cos ( θ )}{8 2} : cos (θ)

\frac{8 2 cos ( θ )}{8 2}

数字相除:

\frac{8}{8} = 1

= \frac{2 cos ( θ )}{2}

约分:

2

= cos (θ)

化简

\frac{- 8}{8 2} : - \frac{2}{2}

\frac{- 8}{8 2}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{8}{8 2}

数字相除:

\frac{8}{8} = 1

= - \frac{1}{2}

- \frac{1}{2}

有理化:

- \frac{2}{2}

- \frac{1}{2}

乘以共轭根式

\frac{2}{2}

= - \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

使用根式运算法则:

a a = a

22 = 2

= 2

= - \frac{2}{2}

= - \frac{2}{2}

cos (θ) = - \frac{2}{2}

cos (θ) = - \frac{2}{2}

cos (θ) = - \frac{2}{2}

cos (θ) = - \frac{2}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

作图

流行的例子

cos(-θ)=-cos(θ)

cos (- θ) = - cos (θ)

sin^2(x)cos(x)=cos(x)

sin^{2} (x) cos (x) = cos (x)

sin(x)= 1/(cos(x))

sin (x) = \frac{1}{cos ( x )}

tan(x)+3cot(x)=5sec(x)

tan (x) + 3 cot (x) = 5 sec (x)

6 sin (θ) + 3 = 0