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Popular Trigonometry >

sec^2(x)tan^2(x)+3sec^2(x)-2tan^2(x)=3

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Solution

sec2(x)tan2(x)+3sec2(x)−2tan2(x)=3

Solution

x=2πn,x=π+2πn
+1
Degrees
x=0∘+360∘n,x=180∘+360∘n
Solution steps
sec2(x)tan2(x)+3sec2(x)−2tan2(x)=3
Subtract 3 from both sidessec2(x)tan2(x)+3sec2(x)−2tan2(x)−3=0
Rewrite using trig identities
−3−2tan2(x)+3sec2(x)+sec2(x)tan2(x)
Use the Pythagorean identity: tan2(x)+1=sec2(x)tan2(x)=sec2(x)−1=−3−2(sec2(x)−1)+3sec2(x)+sec2(x)(sec2(x)−1)
Simplify −3−2(sec2(x)−1)+3sec2(x)+sec2(x)(sec2(x)−1):sec4(x)−1
−3−2(sec2(x)−1)+3sec2(x)+sec2(x)(sec2(x)−1)
Expand −2(sec2(x)−1):−2sec2(x)+2
−2(sec2(x)−1)
Apply the distributive law: a(b−c)=ab−aca=−2,b=sec2(x),c=1=−2sec2(x)−(−2)⋅1
Apply minus-plus rules−(−a)=a=−2sec2(x)+2⋅1
Multiply the numbers: 2⋅1=2=−2sec2(x)+2
=−3−2sec2(x)+2+3sec2(x)+sec2(x)(sec2(x)−1)
Expand sec2(x)(sec2(x)−1):sec4(x)−sec2(x)
sec2(x)(sec2(x)−1)
Apply the distributive law: a(b−c)=ab−aca=sec2(x),b=sec2(x),c=1=sec2(x)sec2(x)−sec2(x)⋅1
=sec2(x)sec2(x)−1⋅sec2(x)
Simplify sec2(x)sec2(x)−1⋅sec2(x):sec4(x)−sec2(x)
sec2(x)sec2(x)−1⋅sec2(x)
sec2(x)sec2(x)=sec4(x)
sec2(x)sec2(x)
Apply exponent rule: ab⋅ac=ab+csec2(x)sec2(x)=sec2+2(x)=sec2+2(x)
Add the numbers: 2+2=4=sec4(x)
1⋅sec2(x)=sec2(x)
1⋅sec2(x)
Multiply: 1⋅sec2(x)=sec2(x)=sec2(x)
=sec4(x)−sec2(x)
=sec4(x)−sec2(x)
=−3−2sec2(x)+2+3sec2(x)+sec4(x)−sec2(x)
Simplify −3−2sec2(x)+2+3sec2(x)+sec4(x)−sec2(x):sec4(x)−1
−3−2sec2(x)+2+3sec2(x)+sec4(x)−sec2(x)
Group like terms=−2sec2(x)+3sec2(x)+sec4(x)−sec2(x)−3+2
Add similar elements: −2sec2(x)+3sec2(x)−sec2(x)=0=sec4(x)−3+2
Add/Subtract the numbers: −3+2=−1=sec4(x)−1
=sec4(x)−1
=sec4(x)−1
−1+sec4(x)=0
Solve by substitution
−1+sec4(x)=0
Let: sec(x)=u−1+u4=0
−1+u4=0:u=1,u=−1,u=i,u=−i
−1+u4=0
Move 1to the right side
−1+u4=0
Add 1 to both sides−1+u4+1=0+1
Simplifyu4=1
u4=1
Rewrite the equation with v=u2 and v2=u4v2=1
Solve v2=1:v=1​,v=−1​
v2=1
For (g(x))2=f(a) the solutions are g(x)=f(a)​,−f(a)​
v=1​,v=−1​
v=1​,v=−1​
Substitute back v=u2,solve for u
Solve u2=1​:u=1,u=−1
u2=1​
Apply rule 1​=1u2=1
For x2=f(a) the solutions are x=f(a)​,−f(a)​
u=1​,u=−1​
1​=1
1​
Apply rule 1​=1=1
−1​=−1
−1​
Apply rule 1​=1=−1
u=1,u=−1
Solve u2=−1​:u=i,u=−i
u2=−1​
Apply rule 1​=1u2=−1
For x2=f(a) the solutions are x=f(a)​,−f(a)​
u=−1​,u=−−1​
Simplify −1​:i
−1​
Apply imaginary number rule: −1​=i=i
Simplify −−1​:−i
−−1​
Apply imaginary number rule: −1​=i=−i
u=i,u=−i
The solutions are
u=1,u=−1,u=i,u=−i
Substitute back u=sec(x)sec(x)=1,sec(x)=−1,sec(x)=i,sec(x)=−i
sec(x)=1,sec(x)=−1,sec(x)=i,sec(x)=−i
sec(x)=1:x=2πn
sec(x)=1
General solutions for sec(x)=1
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
x=0+2πn
x=0+2πn
Solve x=0+2πn:x=2πn
x=0+2πn
0+2πn=2πnx=2πn
x=2πn
sec(x)=−1:x=π+2πn
sec(x)=−1
General solutions for sec(x)=−1
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
x=π+2πn
x=π+2πn
sec(x)=i:No Solution
sec(x)=i
NoSolution
sec(x)=−i:No Solution
sec(x)=−i
NoSolution
Combine all the solutionsx=2πn,x=π+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for sec^2(x)tan^2(x)+3sec^2(x)-2tan^2(x)=3 ?

    The general solution for sec^2(x)tan^2(x)+3sec^2(x)-2tan^2(x)=3 is x=2pin,x=pi+2pin
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