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人気のある三角関数 >

4csc^2(x)-25=0

解

4 csc^{2} (x) - 25 = 0

解

x = 0.41151 \dots + 2 πn, x = π - 0.41151 \dots + 2 πn, x = - 0.41151 \dots + 2 πn, x = π + 0.41151 \dots + 2 πn

+1

度

x = 23.57817 \dots^{\circ} + 36 0^{\circ} n, x = 156.42182 \dots^{\circ} + 36 0^{\circ} n, x = - 23.57817 \dots^{\circ} + 36 0^{\circ} n, x = 203.57817 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

4 csc^{2} (x) - 25 = 0

置換で解く

4 csc^{2} (x) - 25 = 0

仮定:

csc (x) = u

4 u^{2} - 25 = 0

4 u^{2} - 25 = 0 : u = \frac{5}{2}, u = - \frac{5}{2}

4 u^{2} - 25 = 0

25

を右側に移動します

4 u^{2} - 25 = 0

両辺に

25

を足す

4 u^{2} - 25 + 25 = 0 + 25

簡素化

4 u^{2} = 25

4 u^{2} = 25

以下で両辺を割る

4

4 u^{2} = 25

以下で両辺を割る

4

\frac{4 u ^{2}}{4} = \frac{25}{4}

簡素化

u^{2} = \frac{25}{4}

u^{2} = \frac{25}{4}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{25}{4}, u = - \frac{25}{4}

\frac{25}{4} = \frac{5}{2}

\frac{25}{4}

累乗根の規則を適用する:

n \frac{a}{b} = \frac{n a}{n b},

, 以下を想定

a \geq 0, b \geq 0

= \frac{25}{4}

4 = 2

4

数を因数に分解する:

4 = 2^{2}

= 2^{2}

累乗根の規則を適用する:

n a^{n} = a

2^{2} = 2

= 2

= \frac{25}{2}

25 = 5

25

数を因数に分解する:

25 = 5^{2}

= 5^{2}

累乗根の規則を適用する:

n a^{n} = a

5^{2} = 5

= 5

= \frac{5}{2}

- \frac{25}{4} = - \frac{5}{2}

- \frac{25}{4}

簡素化

\frac{25}{4} : \frac{5}{2}

\frac{25}{4}

累乗根の規則を適用する:

n \frac{a}{b} = \frac{n a}{n b},

, 以下を想定

a \geq 0, b \geq 0

= \frac{25}{4}

4 = 2

4

数を因数に分解する:

4 = 2^{2}

= 2^{2}

累乗根の規則を適用する:

n a^{n} = a

2^{2} = 2

= 2

= \frac{25}{2}

25 = 5

25

数を因数に分解する:

25 = 5^{2}

= 5^{2}

累乗根の規則を適用する:

n a^{n} = a

5^{2} = 5

= 5

= \frac{5}{2}

= - \frac{5}{2}

u = \frac{5}{2}, u = - \frac{5}{2}

代用を戻す

u = csc (x)

csc (x) = \frac{5}{2}, csc (x) = - \frac{5}{2}

csc (x) = \frac{5}{2}, csc (x) = - \frac{5}{2}

csc (x) = \frac{5}{2} : x = arccsc (\frac{5}{2}) + 2 πn, x = π - arccsc (\frac{5}{2}) + 2 πn

csc (x) = \frac{5}{2}

三角関数の逆数プロパティを適用する

csc (x) = \frac{5}{2}

以下の一般解

csc (x) = \frac{5}{2}

csc (x) = a \Rightarrow x = arccsc (a) + 2 πn, x = π - arccsc (a) + 2 πn

x = arccsc (\frac{5}{2}) + 2 πn, x = π - arccsc (\frac{5}{2}) + 2 πn

x = arccsc (\frac{5}{2}) + 2 πn, x = π - arccsc (\frac{5}{2}) + 2 πn

csc (x) = - \frac{5}{2} : x = arccsc (- \frac{5}{2}) + 2 πn, x = π + arccsc (\frac{5}{2}) + 2 πn

csc (x) = - \frac{5}{2}

三角関数の逆数プロパティを適用する

csc (x) = - \frac{5}{2}

以下の一般解

csc (x) = - \frac{5}{2}

csc (x) = - a \Rightarrow x = arccsc (- a) + 2 πn, x = π + arccsc (a) + 2 πn

x = arccsc (- \frac{5}{2}) + 2 πn, x = π + arccsc (\frac{5}{2}) + 2 πn

x = arccsc (- \frac{5}{2}) + 2 πn, x = π + arccsc (\frac{5}{2}) + 2 πn

すべての解を組み合わせる

x = arccsc (\frac{5}{2}) + 2 πn, x = π - arccsc (\frac{5}{2}) + 2 πn, x = arccsc (- \frac{5}{2}) + 2 πn, x = π + arccsc (\frac{5}{2}) + 2 πn

10進法形式で解を証明する

x = 0.41151 \dots + 2 πn, x = π - 0.41151 \dots + 2 πn, x = - 0.41151 \dots + 2 πn, x = π + 0.41151 \dots + 2 πn

グラフ

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