ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある三角関数 >

tan^2(x)+csc^2(x)-3=0

解

tan^{2} (x) + csc^{2} (x) - 3 = 0

解

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

+1

度

x = 4 5^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

解答ステップ

tan^{2} (x) + csc^{2} (x) - 3 = 0

三角関数の公式を使用して書き換える

- 3 + csc^{2} (x) + tan^{2} (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{1}{cot ( x )}

= - 3 + csc^{2} (x) + (\frac{1}{cot ( x )})^{2}

(\frac{1}{cot ( x )})^{2} = \frac{1}{cot ^{2} ( x )}

(\frac{1}{cot ( x )})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cot ^{2} ( x )}

規則を適用

1^{a} = 1

1^{2} = 1

= \frac{1}{cot ^{2} ( x )}

= - 3 + csc^{2} (x) + \frac{1}{cot ^{2} ( x )}

ピタゴラスの公式を使用する:

1 + cot^{2} (x) = csc^{2} (x)

cot^{2} (x) = csc^{2} (x) - 1

= - 3 + csc^{2} (x) + \frac{1}{csc ^{2} ( x ) - 1}

- 3 + csc^{2} (x) + \frac{1}{- 1 + csc ^{2} ( x )} = 0

置換で解く

- 3 + csc^{2} (x) + \frac{1}{- 1 + csc ^{2} ( x )} = 0

仮定:

csc (x) = u

- 3 + u^{2} + \frac{1}{- 1 + u ^{2}} = 0

- 3 + u^{2} + \frac{1}{- 1 + u ^{2}} = 0 : u = 2, u = - 2

- 3 + u^{2} + \frac{1}{- 1 + u ^{2}} = 0

以下で両辺を乗じる:

- 1 + u^{2}

- 3 + u^{2} + \frac{1}{- 1 + u ^{2}} = 0

以下で両辺を乗じる:

- 1 + u^{2}

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + \frac{1}{- 1 + u ^{2}} (- 1 + u^{2}) = 0 \cdot (- 1 + u^{2})

簡素化

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + \frac{1}{- 1 + u ^{2}} (- 1 + u^{2}) = 0 \cdot (- 1 + u^{2})

簡素化

\frac{1}{- 1 + u ^{2}} (- 1 + u^{2}) : 1

\frac{1}{- 1 + u ^{2}} (- 1 + u^{2})

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - 1 + u ^{2} )}{- 1 + u ^{2}}

1 \cdot (- 1 + u^{2}) = - 1 + u^{2}

1 \cdot (- 1 + u^{2})

乗算:

1 \cdot (- 1 + u^{2}) = (- 1 + u^{2})

= (- 1 + u^{2})

括弧を削除する:

(- a) = - a

= - 1 + u^{2}

= \frac{- 1 + u ^{2}}{- 1 + u ^{2}}

規則を適用

\frac{a}{a} = 1

= 1

簡素化

0 \cdot (- 1 + u^{2}) : 0

0 \cdot (- 1 + u^{2})

規則を適用

0 \cdot a = 0

= 0

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1 = 0

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1 = 0

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1 = 0

解く

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1 = 0 : u = 2, u = - 2

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1 = 0

拡張

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1 : u^{4} - 4 u^{2} + 4

- 3 (- 1 + u^{2}) + u^{2} (- 1 + u^{2}) + 1

拡張

- 3 (- 1 + u^{2}) : 3 - 3 u^{2}

- 3 (- 1 + u^{2})

分配法則を適用する:

a (b + c) = ab + a c

a = - 3, b = - 1, c = u^{2}

= - 3 (- 1) + (- 3) u^{2}

マイナス・プラスの規則を適用する

- (- a) = a, + (- a) = - a

= 3 \cdot 1 - 3 u^{2}

数を乗じる:

3 \cdot 1 = 3

= 3 - 3 u^{2}

= 3 - 3 u^{2} + u^{2} (- 1 + u^{2}) + 1

拡張

u^{2} (- 1 + u^{2}) : - u^{2} + u^{4}

u^{2} (- 1 + u^{2})

分配法則を適用する:

a (b + c) = ab + a c

a = u^{2}, b = - 1, c = u^{2}

= u^{2} (- 1) + u^{2} u^{2}

マイナス・プラスの規則を適用する

+ (- a) = - a

= - 1 \cdot u^{2} + u^{2} u^{2}

簡素化

- 1 \cdot u^{2} + u^{2} u^{2} : - u^{2} + u^{4}

- 1 \cdot u^{2} + u^{2} u^{2}

1 \cdot u^{2} = u^{2}

1 \cdot u^{2}

乗算:

1 \cdot u^{2} = u^{2}

= u^{2}

u^{2} u^{2} = u^{4}

u^{2} u^{2}

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u^{2} = u^{2 + 2}

= u^{2 + 2}

数を足す:

2 + 2 = 4

= u^{4}

= - u^{2} + u^{4}

= - u^{2} + u^{4}

= 3 - 3 u^{2} - u^{2} + u^{4} + 1

簡素化

3 - 3 u^{2} - u^{2} + u^{4} + 1 : u^{4} - 4 u^{2} + 4

3 - 3 u^{2} - u^{2} + u^{4} + 1

類似した元を足す:

- 3 u^{2} - u^{2} = - 4 u^{2}

= 3 - 4 u^{2} + u^{4} + 1

条件のようなグループ

= u^{4} - 4 u^{2} + 3 + 1

数を足す:

3 + 1 = 4

= u^{4} - 4 u^{2} + 4

= u^{4} - 4 u^{2} + 4

u^{4} - 4 u^{2} + 4 = 0

equationを

v = u^{2}

と以下で書き換える:

v^{2} = u^{4}

v^{2} - 4 v + 4 = 0

解く

v^{2} - 4 v + 4 = 0 : v = 2

v^{2} - 4 v + 4 = 0

解くとthe二次式

v^{2} - 4 v + 4 = 0

二次Equationの公式:

次の場合:

a = 1, b = - 4, c = 4

v_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

v_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

(- 4)^{2} - 4 \cdot 1 \cdot 4

指数の規則を適用する:

n

が偶数であれば

(- a)^{n} = a^{n}

(- 4)^{2} = 4^{2}

= 4^{2} - 4 \cdot 1 \cdot 4

数を乗じる:

4 \cdot 1 \cdot 4 = 16

= 4^{2} - 16

4^{2} = 16

= 16 - 16

数を引く:

16 - 16 = 0

= 0

v_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

v = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

\frac{- ( - 4 )}{2 \cdot 1}

規則を適用

- (- a) = a

= \frac{4}{2 \cdot 1}

数を乗じる:

2 \cdot 1 = 2

= \frac{4}{2}

数を割る:

\frac{4}{2} = 2

= 2

v = 2

二次equationの解:

v = 2

v = 2

再び

v = u^{2}

に置き換えて以下を解く:

u

解く

u^{2} = 2 : u = 2, u = - 2

u^{2} = 2

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = 2, u = - 2

解答は

u = 2, u = - 2

u = 2, u = - 2

解を検算する

未定義の (特異) 点を求める:

u = 1, u = - 1

- 3 + u^{2} + \frac{1}{- 1 + u ^{2}}

の分母をゼロに比較する

解く

- 1 + u^{2} = 0 : u = 1, u = - 1

- 1 + u^{2} = 0

1

を右側に移動します

- 1 + u^{2} = 0

両辺に

1

を足す

- 1 + u^{2} + 1 = 0 + 1

簡素化

u^{2} = 1

u^{2} = 1

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = 1, u = - 1

1 = 1

1

累乗根の規則を適用する:

1 = 1

= 1

- 1 = - 1

- 1

累乗根の規則を適用する:

1 = 1

1 = 1

= - 1

u = 1, u = - 1

以下の点は定義されていない

u = 1, u = - 1

未定義のポイントを解に組み合わせる:

u = 2, u = - 2

代用を戻す

u = csc (x)

csc (x) = 2, csc (x) = - 2

csc (x) = 2, csc (x) = - 2

csc (x) = 2 : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

csc (x) = 2

以下の一般解

csc (x) = 2

csc (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

csc (x) = - 2 : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

csc (x) = - 2

以下の一般解

csc (x) = - 2

csc (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

すべての解を組み合わせる

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

グラフ

人気の例

sin (x) = 0.67

sin (x) = 0.69

4cos^2(x)-4=15cos(x)

4 cos^{2} (x) - 4 = 15 cos (x)

(cos(θ)-1)sin(θ)=0

(cos (θ) - 1) sin (θ) = 0

sin (a) = 0