sin(θ)= 2/3 ,90<θ<180

Lösung

sin (θ) = \frac{2}{3}, 9 0^{\circ} < θ < 18 0^{\circ}

θ = 18 0^{\circ} - 0.72972 \dots

Radianten

θ = π - 0.72972 \dots

Schritte zur Lösung

sin (θ) = \frac{2}{3}, 9 0^{\circ} < θ < 18 0^{\circ}

Wende die Eigenschaften der Trigonometrie an

sin (θ) = \frac{2}{3}

Allgemeine Lösung für

sin (θ) = \frac{2}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

θ = arcsin (\frac{2}{3}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{2}{3}) + 36 0^{\circ} n

θ = arcsin (\frac{2}{3}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{2}{3}) + 36 0^{\circ} n

Lösungen für den Bereich

9 0^{\circ} < θ < 18 0^{\circ}

θ = 18 0^{\circ} - arcsin (\frac{2}{3})

Zeige Lösungen in Dezimalform

θ = 18 0^{\circ} - 0.72972 \dots

4 sin^{2} (3 x) - 2 = 0

cos (\frac{π}{6} x) = 0

4 cos (θ) = - 4 sin (- θ)

tan (5 x) + tan (3 x) = 0

5 sin (2 x) = 5 cos (x)