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Popular Trigonometry >

solvefor x,sin(x)+cos(y)=sin(x)cos(y)

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Solution

solve for x,sin(x)+cos(y)=sin(x)cos(y)

Solution

x=arccsc(cos(y)cos(y)−1​)+2πn,x=π+arccsc(−cos(y)cos(y)−1​)+2πn
Solution steps
sin(x)+cos(y)=sin(x)cos(y)
Subtract sin(x)cos(y) from both sidessin(x)+cos(y)−cos(y)sin(x)=0
Rewrite using trig identities
cos(y)+sin(x)−cos(y)sin(x)
Use the basic trigonometric identity: sin(x)=csc(x)1​=cos(y)+csc(x)1​−cos(y)csc(x)1​
Simplify cos(y)+csc(x)1​−cos(y)csc(x)1​:cos(y)+csc(x)1−cos(y)​
cos(y)+csc(x)1​−cos(y)csc(x)1​
cos(y)csc(x)1​=csc(x)cos(y)​
cos(y)csc(x)1​
Multiply fractions: a⋅cb​=ca⋅b​=csc(x)1⋅cos(y)​
Multiply: 1⋅cos(y)=cos(y)=csc(x)cos(y)​
=cos(y)+csc(x)1​−csc(x)cos(y)​
Combine the fractions csc(x)1​−csc(x)cos(y)​:csc(x)1−cos(y)​
Apply rule ca​±cb​=ca±b​=csc(x)1−cos(y)​
=cos(y)+csc(x)−cos(y)+1​
=cos(y)+csc(x)1−cos(y)​
cos(y)+csc(x)1−cos(y)​=0
Multiply both sides by csc(x)
cos(y)+csc(x)1−cos(y)​=0
Multiply both sides by csc(x)cos(y)csc(x)+csc(x)1−cos(y)​csc(x)=0⋅csc(x)
Simplify
cos(y)csc(x)+csc(x)1−cos(y)​csc(x)=0⋅csc(x)
Simplify csc(x)1−cos(y)​csc(x):1−cos(y)
csc(x)1−cos(y)​csc(x)
Multiply fractions: a⋅cb​=ca⋅b​=csc(x)(1−cos(y))csc(x)​
Cancel the common factor: csc(x)=1−cos(y)
Simplify 0⋅csc(x):0
0⋅csc(x)
Apply rule 0⋅a=0=0
cos(y)csc(x)+1−cos(y)=0
cos(y)csc(x)+1−cos(y)=0
cos(y)csc(x)+1−cos(y)=0
Move cos(y)to the right side
cos(y)csc(x)+1−cos(y)=0
Add cos(y) to both sidescos(y)csc(x)+1−cos(y)+cos(y)=0+cos(y)
Simplifycos(y)csc(x)+1=cos(y)
cos(y)csc(x)+1=cos(y)
Move 1to the right side
cos(y)csc(x)+1=cos(y)
Subtract 1 from both sidescos(y)csc(x)+1−1=cos(y)−1
Simplifycos(y)csc(x)=cos(y)−1
cos(y)csc(x)=cos(y)−1
Divide both sides by cos(y);y=2π​+2πn,y=23π​+2πn
cos(y)csc(x)=cos(y)−1
Divide both sides by cos(y);y=2π​+2πn,y=23π​+2πncos(y)cos(y)csc(x)​=cos(y)cos(y)​−cos(y)1​;y=2π​+2πn,y=23π​+2πn
Simplify
cos(y)cos(y)csc(x)​=cos(y)cos(y)​−cos(y)1​
Simplify cos(y)cos(y)csc(x)​:csc(x)
cos(y)cos(y)csc(x)​
Cancel the common factor: cos(y)=csc(x)
Simplify cos(y)cos(y)​−cos(y)1​:cos(y)cos(y)−1​
cos(y)cos(y)​−cos(y)1​
Apply rule ca​±cb​=ca±b​=cos(y)cos(y)−1​
csc(x)=cos(y)cos(y)−1​;y=2π​+2πn,y=23π​+2πn
csc(x)=cos(y)cos(y)−1​;y=2π​+2πn,y=23π​+2πn
csc(x)=cos(y)cos(y)−1​;y=2π​+2πn,y=23π​+2πn
Apply trig inverse properties
csc(x)=cos(y)cos(y)−1​
General solutions for csc(x)=cos(y)cos(y)−1​csc(x)=a⇒x=arccsc(a)+2πn,x=π+arccsc(a)+2πnx=arccsc(cos(y)cos(y)−1​)+2πn,x=π+arccsc(−cos(y)cos(y)−1​)+2πn
x=arccsc(cos(y)cos(y)−1​)+2πn,x=π+arccsc(−cos(y)cos(y)−1​)+2πn

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