What is the general solution for sin(3θ+72)=cos(48),0<= θ<= 360 ?

Q: What is the general solution for sin(3θ+72)=cos(48),0<= θ<= 360 ?

The general solution for sin(3θ+72)=cos(48),0<= θ<= 360 is θ=22,θ=110,θ=142,θ=230,θ=262,θ=350

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Popular Trigonometry >

sin(3θ+72)=cos(48),0<= θ<= 360

Solution

sin (3 θ + 7 2^{\circ}) = cos (4 8^{\circ}), 0^{\circ} \leq θ \leq 36 0^{\circ}

Solution

θ = 2 2^{\circ}, θ = 11 0^{\circ}, θ = 14 2^{\circ}, θ = 23 0^{\circ}, θ = 26 2^{\circ}, θ = 35 0^{\circ}

Radians

θ = \frac{11 π}{90}, θ = \frac{11 π}{18}, θ = \frac{71 π}{90}, θ = \frac{23 π}{18}, θ = \frac{131 π}{90}, θ = \frac{35 π}{18}

Solution steps

sin (3 θ + 7 2^{\circ}) = cos (4 8^{\circ}), 0^{\circ} \leq θ \leq 36 0^{\circ}

Rewrite using trig identities

cos (4 8^{\circ})

Use the following identity:

cos (x) = sin (9 0^{\circ} - x)

sin (9 0^{\circ} - 4 8^{\circ})

sin (3 θ + 7 2^{\circ}) = sin (9 0^{\circ} - 4 8^{\circ})

Apply trig inverse properties

sin (3 θ + 7 2^{\circ}) = sin (9 0^{\circ} - 4 8^{\circ})

sin (x) = sin (y) \Rightarrow x = y + 2 π n, x = π - y + 2 π n

3 θ + 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n, 3 θ + 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n

3 θ + 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n, 3 θ + 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n

3 θ + 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n : θ = \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}

3 θ + 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n

Move

7 2^{\circ}

to the right side

3 θ + 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n

Subtract

7 2^{\circ}

from both sides

3 θ + 7 2^{\circ} - 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n - 7 2^{\circ}

Simplify

3 θ + 7 2^{\circ} - 7 2^{\circ} = 9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n - 7 2^{\circ}

Simplify

3 θ + 7 2^{\circ} - 7 2^{\circ} : 3 θ

3 θ + 7 2^{\circ} - 7 2^{\circ}

Add similar elements:

7 2^{\circ} - 7 2^{\circ} = 0

= 3 θ

Simplify

9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n - 7 2^{\circ} : 36 0^{\circ} n - 3 0^{\circ}

9 0^{\circ} - 4 8^{\circ} + 36 0^{\circ} n - 7 2^{\circ}

Group like terms

= 36 0^{\circ} n + 9 0^{\circ} - 7 2^{\circ} - 4 8^{\circ}

Least Common Multiplier of

2, 5, 15 : 30

2, 5, 15

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

5 : 5

5

5

is a prime number, therefore no factorization is possible

= 5

Prime factorization of

15 : 3 \cdot 5

15

15

divides by

315 = 5 \cdot 3

= 3 \cdot 5

3, 5

are all prime numbers, therefore no further factorization is possible

= 3 \cdot 5

Compute a number comprised of factors that appear in at least one of the following:

2, 5, 15

= 2 \cdot 5 \cdot 3

Multiply the numbers:

2 \cdot 5 \cdot 3 = 30

= 30

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

30

For

9 0^{\circ} :

multiply the denominator and numerator by

15

9 0^{\circ} = \frac{18 0 ^{\circ} 15}{2 \cdot 15} = 9 0^{\circ}

For

7 2^{\circ} :

multiply the denominator and numerator by

6

7 2^{\circ} = \frac{36 0 ^{\circ} 6}{5 \cdot 6} = 7 2^{\circ}

For

4 8^{\circ} :

multiply the denominator and numerator by

2

4 8^{\circ} = \frac{72 0 ^{\circ} 2}{15 \cdot 2} = 4 8^{\circ}

= 9 0^{\circ} - 7 2^{\circ} - 4 8^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 15 - 216 0 ^{\circ} - 144 0 ^{\circ}}{30}

Add similar elements:

270 0^{\circ} - 216 0^{\circ} - 144 0^{\circ} = - 90 0^{\circ}

= \frac{- 90 0 ^{\circ}}{30}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - 3 0^{\circ}

Cancel the common factor:

5

= 36 0^{\circ} n - 3 0^{\circ}

3 θ = 36 0^{\circ} n - 3 0^{\circ}

3 θ = 36 0^{\circ} n - 3 0^{\circ}

3 θ = 36 0^{\circ} n - 3 0^{\circ}

Divide both sides by

3

3 θ = 36 0^{\circ} n - 3 0^{\circ}

Divide both sides by

3

\frac{3 θ}{3} = \frac{36 0 ^{\circ} n}{3} - \frac{3 0 ^{\circ}}{3}

Simplify

\frac{3 θ}{3} = \frac{36 0 ^{\circ} n}{3} - \frac{3 0 ^{\circ}}{3}

Simplify

\frac{3 θ}{3} : θ

\frac{3 θ}{3}

Divide the numbers:

\frac{3}{3} = 1

= θ

Simplify

\frac{36 0 ^{\circ} n}{3} - \frac{3 0 ^{\circ}}{3} : \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}

\frac{36 0 ^{\circ} n}{3} - \frac{3 0 ^{\circ}}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{36 0 ^{\circ} n - 3 0 ^{\circ}}{3}

Join

36 0^{\circ} n - 3 0^{\circ} : \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{6}

36 0^{\circ} n - 3 0^{\circ}

Convert element to fraction:

36 0^{\circ} n = \frac{36 0 ^{\circ} n 6}{6}

= \frac{36 0 ^{\circ} n \cdot 6}{6} - 3 0^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{36 0 ^{\circ} n \cdot 6 - 18 0 ^{\circ}}{6}

Multiply the numbers:

2 \cdot 6 = 12

= \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{6}

= \frac{\frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{6}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{6 \cdot 3}

Multiply the numbers:

6 \cdot 3 = 18

= \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}

θ = \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}

θ = \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}

θ = \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}

3 θ + 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n : θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

3 θ + 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n

Move

7 2^{\circ}

to the right side

3 θ + 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n

Subtract

7 2^{\circ}

from both sides

3 θ + 7 2^{\circ} - 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n - 7 2^{\circ}

Simplify

3 θ + 7 2^{\circ} - 7 2^{\circ} = 18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n - 7 2^{\circ}

Simplify

3 θ + 7 2^{\circ} - 7 2^{\circ} : 3 θ

3 θ + 7 2^{\circ} - 7 2^{\circ}

Add similar elements:

7 2^{\circ} - 7 2^{\circ} = 0

= 3 θ

Simplify

18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n - 7 2^{\circ} : 18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

18 0^{\circ} - (9 0^{\circ} - 4 8^{\circ}) + 36 0^{\circ} n - 7 2^{\circ}

Join

9 0^{\circ} - 4 8^{\circ} : 4 2^{\circ}

9 0^{\circ} - 4 8^{\circ}

Least Common Multiplier of

2, 15 : 30

2, 15

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

15 : 3 \cdot 5

15

15

divides by

315 = 5 \cdot 3

= 3 \cdot 5

3, 5

are all prime numbers, therefore no further factorization is possible

= 3 \cdot 5

Multiply each factor the greatest number of times it occurs in either

2

15

= 2 \cdot 3 \cdot 5

Multiply the numbers:

2 \cdot 3 \cdot 5 = 30

= 30

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

30

For

9 0^{\circ} :

multiply the denominator and numerator by

15

9 0^{\circ} = \frac{18 0 ^{\circ} 15}{2 \cdot 15} = 9 0^{\circ}

For

4 8^{\circ} :

multiply the denominator and numerator by

2

4 8^{\circ} = \frac{72 0 ^{\circ} 2}{15 \cdot 2} = 4 8^{\circ}

= 9 0^{\circ} - 4 8^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 15 - 144 0 ^{\circ}}{30}

Add similar elements:

270 0^{\circ} - 144 0^{\circ} = 126 0^{\circ}

= 4 2^{\circ}

= 18 0^{\circ} - 4 2^{\circ} + 36 0^{\circ} n - 7 2^{\circ}

Group like terms

= 18 0^{\circ} + 36 0^{\circ} n - 7 2^{\circ} - 4 2^{\circ}

Least Common Multiplier of

5, 30 : 30

5, 30

Least Common Multiplier (LCM)

Prime factorization of

5 : 5

5

5

is a prime number, therefore no factorization is possible

= 5

Prime factorization of

30 : 2 \cdot 3 \cdot 5

30

30

divides by

230 = 15 \cdot 2

= 2 \cdot 15

15

divides by

315 = 5 \cdot 3

= 2 \cdot 3 \cdot 5

2, 3, 5

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3 \cdot 5

Multiply each factor the greatest number of times it occurs in either

5

30

= 5 \cdot 2 \cdot 3

Multiply the numbers:

5 \cdot 2 \cdot 3 = 30

= 30

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

30

For

7 2^{\circ} :

multiply the denominator and numerator by

6

7 2^{\circ} = \frac{36 0 ^{\circ} 6}{5 \cdot 6} = 7 2^{\circ}

= - 7 2^{\circ} - 4 2^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 216 0 ^{\circ} - 126 0 ^{\circ}}{30}

Add similar elements:

- 216 0^{\circ} - 126 0^{\circ} = - 342 0^{\circ}

= \frac{- 342 0 ^{\circ}}{30}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= 18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

3 θ = 18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

3 θ = 18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

3 θ = 18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

Divide both sides by

3

3 θ = 18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

Divide both sides by

3

\frac{3 θ}{3} = 6 0^{\circ} + \frac{36 0 ^{\circ} n}{3} - \frac{11 4 ^{\circ}}{3}

Simplify

\frac{3 θ}{3} = 6 0^{\circ} + \frac{36 0 ^{\circ} n}{3} - \frac{11 4 ^{\circ}}{3}

Simplify

\frac{3 θ}{3} : θ

\frac{3 θ}{3}

Divide the numbers:

\frac{3}{3} = 1

= θ

Simplify

6 0^{\circ} + \frac{36 0 ^{\circ} n}{3} - \frac{11 4 ^{\circ}}{3} : \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

6 0^{\circ} + \frac{36 0 ^{\circ} n}{3} - \frac{11 4 ^{\circ}}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} + 36 0 ^{\circ} n - 11 4 ^{\circ}}{3}

Join

18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ} : \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{30}

18 0^{\circ} + 36 0^{\circ} n - 11 4^{\circ}

Convert element to fraction:

18 0^{\circ} = 18 0^{\circ}, 36 0^{\circ} n = \frac{36 0 ^{\circ} n 30}{30}

= 18 0^{\circ} + \frac{36 0 ^{\circ} n \cdot 30}{30} - 11 4^{\circ}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 0 ^{\circ} 30 + 36 0 ^{\circ} n \cdot 30 - 342 0 ^{\circ}}{30}

18 0^{\circ} 30 + 36 0^{\circ} n \cdot 30 - 342 0^{\circ} = 198 0^{\circ} + 1080 0^{\circ} n

18 0^{\circ} 30 + 36 0^{\circ} n \cdot 30 - 342 0^{\circ}

Add similar elements:

540 0^{\circ} - 342 0^{\circ} = 198 0^{\circ}

= 198 0^{\circ} + 2 \cdot 540 0^{\circ} n

Multiply the numbers:

2 \cdot 30 = 60

= 198 0^{\circ} + 1080 0^{\circ} n

= \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{30}

= \frac{\frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{30}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{30 \cdot 3}

Multiply the numbers:

30 \cdot 3 = 90

= \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

θ = \frac{216 0 ^{\circ} n - 18 0 ^{\circ}}{18}, θ = \frac{198 0 ^{\circ} + 1080 0 ^{\circ} n}{90}

Solutions for the range

0 \leq θ \leq 36 0^{\circ}

θ = 2 2^{\circ}, θ = 11 0^{\circ}, θ = 14 2^{\circ}, θ = 23 0^{\circ}, θ = 26 2^{\circ}, θ = 35 0^{\circ}

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for sin(3θ+72)=cos(48),0<= θ<= 360 ?
The general solution for sin(3θ+72)=cos(48),0<= θ<= 360 is θ=22,θ=110,θ=142,θ=230,θ=262,θ=350