What is the general solution for cos(θ)= 20/25 ?

The general solution for cos(θ)= 20/25 is θ=0.64350…+2pin,θ=2pi-0.64350…+2pin

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cos(θ)= 20/25

cos (θ) = \frac{20}{25}

θ = 0.64350 \dots + 2 πn, θ = 2 π - 0.64350 \dots + 2 πn

Degrees

θ = 36.86989 \dots^{\circ} + 36 0^{\circ} n, θ = 323.13010 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = \frac{20}{25}

Cancel the common factor:

5

cos (θ) = \frac{4}{5}

Apply trig inverse properties

cos (θ) = \frac{4}{5}

General solutions for

cos (θ) = \frac{4}{5}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{4}{5}) + 2 πn, θ = 2 π - arccos (\frac{4}{5}) + 2 πn

θ = arccos (\frac{4}{5}) + 2 πn, θ = 2 π - arccos (\frac{4}{5}) + 2 πn

Show solutions in decimal form

θ = 0.64350 \dots + 2 πn, θ = 2 π - 0.64350 \dots + 2 πn

What is the general solution for cos(θ)= 20/25 ?
The general solution for cos(θ)= 20/25 is θ=0.64350…+2pin,θ=2pi-0.64350…+2pin