beweisen 1+tan^2(a)=sec^2(a)

Lösung

beweisen

1 + tan^{2} (a) = sec^{2} (a)

Wahr

Schritte zur Lösung

1 + tan^{2} (a) = sec^{2} (a)

Verwende die Pythagoreische Identität:

tan^{2} (x) + 1 = sec^{2} (x)

\Rightarrow Wahr

p ro v e 2 cos (x) cos (y) = cos (x + y) + cos (x - y)

p ro v e \frac{1}{sec ^{2} ( θ )} + \frac{1}{csc ^{2} ( θ )} = 1

p ro v e cos (x + π) cos (x - π) = cos^{2} (x)

p ro v e (1 + tan^{2} (u)) (1 - sin^{2} (u)) = 1

p ro v e sec^{3} (x) = \frac{1}{cos ^{3} ( x )}