Is sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) ?

The answer to whether sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) is False

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prove sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ))

prove

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

False

Solution steps

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

Show that the two sides are not equal

For

sin (θ) - tan (θ) = \frac{sin ( θ )}{1 - cos ( θ )}

plug in

θ = 1

sin (1) - tan (1) = - 0.71593 \dots

sin (1) - tan (1)

Refine to a decimal form

= - 0.71593 \dots

\frac{sin ( 1 )}{1 - cos ( 1 )} = 1.83048 \dots

\frac{sin ( 1 )}{1 - cos ( 1 )}

Refine to a decimal form

= 1.83048 \dots

The two sides are not equal

\Rightarrow False

Is sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) ?
The answer to whether sin(θ)-tan(θ)=(sin(θ))/(1-cos(θ)) is False