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人気のある三角関数 >

solvefor x,f=arctan(x/(sqrt(1-x^2)))

解

解く

x, f = arctan (\frac{x}{1 - x ^{2}})

解

x = \frac{tan ( f )}{1 + tan ^{2} ( f )}

解答ステップ

f = arctan (\frac{x}{1 - x ^{2}})

辺を交換する

arctan (\frac{x}{1 - x ^{2}}) = f

三角関数の逆数プロパティを適用する

arctan (\frac{x}{1 - x ^{2}}) = f

arctan (x) = a \Rightarrow x = tan (a)

\frac{x}{1 - x ^{2}} = tan (f)

\frac{x}{1 - x ^{2}} = tan (f)

解く

\frac{x}{1 - x ^{2}} = tan (f) : x = \frac{tan ( f )}{1 + tan ^{2} ( f )}

\frac{x}{1 - x ^{2}} = tan (f)

以下で両辺を乗じる:

1 - x^{2}

\frac{x}{1 - x ^{2}} 1 - x^{2} = tan (f) 1 - x^{2}

簡素化

x = tan (f) 1 - x^{2}

両辺を2乗する:

x^{2} = tan^{2} (f) - x^{2} tan^{2} (f)

x = tan (f) 1 - x^{2}

x^{2} = (tan (f) 1 - x^{2})^{2}

拡張

(tan (f) 1 - x^{2})^{2} : tan^{2} (f) - x^{2} tan^{2} (f)

(tan (f) 1 - x^{2})^{2}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

= tan^{2} (f) (1 - x^{2})^{2}

(1 - x^{2})^{2} : 1 - x^{2}

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= ((1 - x^{2})^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 - x^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 - x^{2}

= tan^{2} (f) (1 - x^{2})

拡張

(1 - x^{2}) tan^{2} (f) : tan^{2} (f) - x^{2} tan^{2} (f)

(1 - x^{2}) tan^{2} (f)

= tan^{2} (f) (1 - x^{2})

分配法則を適用する:

a (b - c) = ab - a c

a = tan^{2} (f), b = 1, c = x^{2}

= tan^{2} (f) \cdot 1 - tan^{2} (f) x^{2}

= 1 \cdot tan^{2} (f) - x^{2} tan^{2} (f)

乗算:

1 \cdot tan^{2} (f) = tan^{2} (f)

= tan^{2} (f) - x^{2} tan^{2} (f)

= tan^{2} (f) - x^{2} tan^{2} (f)

x^{2} = tan^{2} (f) - x^{2} tan^{2} (f)

x^{2} = tan^{2} (f) - x^{2} tan^{2} (f)

解く

x^{2} = tan^{2} (f) - x^{2} tan^{2} (f) : x = \frac{tan ( f )}{1 + tan ^{2} ( f )}, x = - \frac{tan ( f )}{1 + tan ^{2} ( f )}

x^{2} = tan^{2} (f) - x^{2} tan^{2} (f)

x^{2} tan^{2} (f)

を左側に移動します

x^{2} = tan^{2} (f) - x^{2} tan^{2} (f)

両辺に

x^{2} tan^{2} (f)

を足す

x^{2} + x^{2} tan^{2} (f) = tan^{2} (f) - x^{2} tan^{2} (f) + x^{2} tan^{2} (f)

簡素化

x^{2} + x^{2} tan^{2} (f) = tan^{2} (f)

x^{2} + x^{2} tan^{2} (f) = tan^{2} (f)

因数

x^{2} + x^{2} tan^{2} (f) : x^{2} (1 + tan^{2} (f))

x^{2} + x^{2} tan^{2} (f)

共通項をくくり出す

x^{2}

= x^{2} (1 + tan^{2} (f))

x^{2} (1 + tan^{2} (f)) = tan^{2} (f)

以下で両辺を割る

1 + tan^{2} (f)

x^{2} (1 + tan^{2} (f)) = tan^{2} (f)

以下で両辺を割る

1 + tan^{2} (f)

\frac{x ^{2} ( 1 + tan ^{2} ( f ) )}{1 + tan ^{2} ( f )} = \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

簡素化

x^{2} = \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

x^{2} = \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}, x = - \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

簡素化

\frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )} : \frac{tan ( f )}{1 + tan ^{2} ( f )}

\frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

累乗根の規則を適用する:

n \frac{a}{b} = \frac{n a}{n b},

, 以下を想定

a \geq 0, b \geq 0

= \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

累乗根の規則を適用する:

n a^{n} = a,

, 以下を想定

a \geq 0

tan^{2} (f) = tan (f)

= \frac{tan ( f )}{1 + tan ^{2} ( f )}

簡素化

- \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )} : - \frac{tan ( f )}{1 + tan ^{2} ( f )}

- \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

簡素化

\frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )} : \frac{tan ( f )}{1 + tan ^{2} ( f )}

\frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

累乗根の規則を適用する:

n \frac{a}{b} = \frac{n a}{n b},

, 以下を想定

a \geq 0, b \geq 0

= \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

累乗根の規則を適用する:

n a^{n} = a,

, 以下を想定

a \geq 0

tan^{2} (f) = tan (f)

= \frac{tan ( f )}{1 + tan ^{2} ( f )}

= - \frac{tan ( f )}{tan ^{2} ( f ) + 1}

= - \frac{tan ( f )}{1 + tan ^{2} ( f )}

x = \frac{tan ( f )}{1 + tan ^{2} ( f )}, x = - \frac{tan ( f )}{1 + tan ^{2} ( f )}

x = \frac{tan ( f )}{1 + tan ^{2} ( f )}, x = - \frac{tan ( f )}{1 + tan ^{2} ( f )}

解を検算する:

x = \frac{tan ( f )}{1 + tan ^{2} ( f )}

真

, x = - \frac{tan ( f )}{1 + tan ^{2} ( f )}

偽

\frac{x}{1 - x ^{2}} = tan (f)

に当てはめて解を確認する

equationに一致しないものを削除する。

挿入

x = \frac{tan ( f )}{1 + tan ^{2} ( f )} :

真

\frac{( \frac{t a n ( f )}{1 + t a n ^{2} ( f )} )}{1 - ( \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}} = tan (f)

簡素化

\frac{( \frac{t a n ( f )}{1 + t a n ^{2} ( f )} )}{1 - ( \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}} : tan (f)

\frac{\frac{t a n ( f )}{1 + t a n ^{2} ( f )}}{1 - ( \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{tan ( f )}{1 + tan ^{2} ( f ) 1 - ( \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}}

1 - (\frac{tan ( f )}{1 + tan ^{2} ( f )})^{2} = \frac{1}{1 + tan ^{2} ( f )}

1 - (\frac{tan ( f )}{1 + tan ^{2} ( f )})^{2}

(\frac{tan ( f )}{1 + tan ^{2} ( f )})^{2} = \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

(\frac{tan ( f )}{1 + tan ^{2} ( f )})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{tan ^{2} ( f )}{( 1 + tan ^{2} ( f ) ) ^{2}}

(1 + tan^{2} (f))^{2} : 1 + tan^{2} (f)

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= ((1 + tan^{2} (f))^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 + tan^{2} (f))^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 + tan^{2} (f)

= \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

= 1 - \frac{tan ^{2} ( f )}{tan ^{2} ( f ) + 1}

結合

1 - \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )} : \frac{1}{1 + tan ^{2} ( f )}

1 - \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

元を分数に変換する:

1 = \frac{1 ( 1 + tan ^{2} ( f ) )}{1 + tan ^{2} ( f )}

= \frac{1 \cdot ( 1 + tan ^{2} ( f ) )}{1 + tan ^{2} ( f )} - \frac{tan ^{2} ( f )}{1 + tan ^{2} ( f )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot ( 1 + tan ^{2} ( f ) ) - tan ^{2} ( f )}{1 + tan ^{2} ( f )}

1 \cdot (1 + tan^{2} (f)) - tan^{2} (f) = 1

1 \cdot (1 + tan^{2} (f)) - tan^{2} (f)

1 \cdot (1 + tan^{2} (f)) = 1 + tan^{2} (f)

1 \cdot (1 + tan^{2} (f))

乗算:

1 \cdot (1 + tan^{2} (f)) = (1 + tan^{2} (f))

= 1 + tan^{2} (f)

括弧を削除する:

(a) = a

= 1 + tan^{2} (f)

= 1 + tan^{2} (f) - tan^{2} (f)

類似した元を足す:

tan^{2} (f) - tan^{2} (f) = 0

= 1

= \frac{1}{1 + tan ^{2} ( f )}

= \frac{1}{1 + tan ^{2} ( f )}

累乗根の規則を適用する:

n \frac{a}{b} = \frac{n a}{n b},

, 以下を想定

a \geq 0, b \geq 0

= \frac{1}{1 + tan ^{2} ( f )}

規則を適用

1 = 1

= \frac{1}{1 + tan ^{2} ( f )}

= \frac{tan ( f )}{\frac{1}{t a n ^{2} ( f ) + 1} tan ^{2} ( f ) + 1}

乗じる

1 + tan^{2} (f) \frac{1}{1 + tan ^{2} ( f )} : 1

1 + tan^{2} (f) \frac{1}{1 + tan ^{2} ( f )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 1 + tan ^{2} ( f )}{1 + tan ^{2} ( f )}

共通因数を約分する:

1 + tan^{2} (f)

= 1

= \frac{tan ( f )}{1}

規則を適用

\frac{a}{1} = a

= tan (f)

tan (f) = tan (f)

真

以下を当てはめる:

x = - \frac{tan ( f )}{1 + tan ^{2} ( f )} : \frac{- \frac{t a n ( f )}{1 + t a n ^{2} ( f )}}{1 - ( - \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}} = tan (f) \Rightarrow

偽

\frac{( - \frac{t a n ( f )}{1 + t a n ^{2} ( f )} )}{1 - ( - \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}} = tan (f)

置換で解く

\frac{- \frac{t a n ( f )}{1 + t a n ^{2} ( f )}}{1 - ( - \frac{t a n ( f )}{1 + t a n ^{2} ( f )} ) ^{2}} = tan (f)

仮定:

tan (f) = u

\frac{- \frac{u}{1 + u ^{2}}}{1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}} = u

\frac{- \frac{u}{1 + u ^{2}}}{1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}} = u :

すべての

u

で真

\frac{- \frac{u}{1 + u ^{2}}}{1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}} = u

以下で両辺を乗じる:

1 - (\frac{u}{1 + u ^{2}})^{2}

\frac{- \frac{u}{1 + u ^{2}}}{1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}} 1 - (\frac{u}{1 + u ^{2}})^{2} = u 1 - (\frac{u}{1 + u ^{2}})^{2}

簡素化

- \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}} = u 1 - (\frac{u}{1 + u ^{2}})^{2}

両辺を2乗する:

\frac{u ^{2}}{1 + u ^{2}} = \frac{u ^{2}}{1 + u ^{2}}

- \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}} = u 1 - (\frac{u}{1 + u ^{2}})^{2}

- \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}}^{2} = u 1 - (\frac{u}{1 + u ^{2}})^{2}^{2}

拡張

- \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}}^{2} : \frac{u ^{2}}{1 + u ^{2}}

- \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}}^{2}

指数の規則を適用する:

n

が偶数であれば

(- a)^{n} = a^{n}

- \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}}^{2} = \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}}^{2}

= \frac{1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u}{1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2}}^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u ) ^{2}}{( 1 + u ^{2} 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2}}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

1 + u^{2} 1 - (- \frac{u}{1 + u ^{2}})^{2}^{2} = (1 + u^{2})^{2} 1 - (- \frac{u}{1 + u ^{2}})^{2}^{2}

= \frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} u ) ^{2}}{( 1 + u ^{2} ) ^{2} ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2}}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

1 - (\frac{u}{1 + u ^{2}})^{2} u^{2} = u^{2} 1 - (\frac{u}{1 + u ^{2}})^{2}^{2}

= \frac{u ^{2} ( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2}}{( 1 + u ^{2} ) ^{2} ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2}}

(1 + u^{2})^{2} : 1 + u^{2}

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= ((1 + u^{2})^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 + u^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 + u^{2}

= \frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2} u ^{2}}{( 1 + u ^{2} ) ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2}}

1 - (\frac{u}{1 + u ^{2}})^{2}^{2} : 1 - (\frac{u}{1 + u ^{2}})^{2}

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= (1 - (\frac{u}{1 + u ^{2}})^{2})^{\frac{1}{2}}^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 - (\frac{u}{1 + u ^{2}})^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 - (\frac{u}{1 + u ^{2}})^{2}

= \frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} ) u ^{2}}{( 1 + u ^{2} ) ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} ) ^{2}}

1 - (- \frac{u}{1 + u ^{2}})^{2}^{2} : 1 - (- \frac{u}{1 + u ^{2}})^{2}

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= (1 - (- \frac{u}{1 + u ^{2}})^{2})^{\frac{1}{2}}^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 - (- \frac{u}{1 + u ^{2}})^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 - (- \frac{u}{1 + u ^{2}})^{2}

= \frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} ) u ^{2}}{( 1 + u ^{2} ) ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} )}

拡張

\frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} ) u ^{2}}{( 1 + u ^{2} ) ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} )} : \frac{u ^{2}}{1 + u ^{2}}

\frac{( 1 - ( \frac{u}{1 + u ^{2}} ) ^{2} ) u ^{2}}{( 1 + u ^{2} ) ( 1 - ( - \frac{u}{1 + u ^{2}} ) ^{2} )}

(1 + u^{2}) (1 - (- \frac{u}{1 + u ^{2}})^{2}) = (1 + u^{2}) (1 - (\frac{u}{1 + u ^{2}})^{2})

(1 + u^{2}) (1 - (- \frac{u}{1 + u ^{2}})^{2})

指数の規則を適用する:

n

が偶数であれば

(- a)^{n} = a^{n}

(- \frac{u}{u ^{2} + 1})^{2} = (\frac{u}{1 + u ^{2}})^{2}

= (u^{2} + 1) (- (\frac{u}{u ^{2} + 1})^{2} + 1)

= \frac{u ^{2} ( - ( \frac{u}{u ^{2} + 1} ) ^{2} + 1 )}{( u ^{2} + 1 ) ( - ( \frac{u}{u ^{2} + 1} ) ^{2} + 1 )}

共通因数を約分する:

1 - (\frac{u}{1 + u ^{2}})^{2}

= \frac{u ^{2}}{1 + u ^{2}}

= \frac{u ^{2}}{1 + u ^{2}}

拡張

u 1 - (\frac{u}{1 + u ^{2}})^{2}^{2} : \frac{u ^{2}}{1 + u ^{2}}

u 1 - (\frac{u}{1 + u ^{2}})^{2}^{2}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

= u^{2} 1 - (\frac{u}{1 + u ^{2}})^{2}^{2}

1 - (\frac{u}{1 + u ^{2}})^{2}^{2} : 1 - (\frac{u}{1 + u ^{2}})^{2}

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= (1 - (\frac{u}{1 + u ^{2}})^{2})^{\frac{1}{2}}^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 - (\frac{u}{1 + u ^{2}})^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 - (\frac{u}{1 + u ^{2}})^{2}

= u^{2} (1 - (\frac{u}{1 + u ^{2}})^{2})

拡張

(1 - (\frac{u}{1 + u ^{2}})^{2}) u^{2} : \frac{u ^{2}}{1 + u ^{2}}

(1 - (\frac{u}{1 + u ^{2}})^{2}) u^{2}

(\frac{u}{1 + u ^{2}})^{2} = \frac{u ^{2}}{1 + u ^{2}}

(\frac{u}{1 + u ^{2}})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{u ^{2}}{( 1 + u ^{2} ) ^{2}}

(1 + u^{2})^{2} : 1 + u^{2}

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= ((1 + u^{2})^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= (1 + u^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 1 + u^{2}

= \frac{u ^{2}}{1 + u ^{2}}

= u^{2} (- \frac{u ^{2}}{u ^{2} + 1} + 1)

= u^{2} (1 - \frac{u ^{2}}{1 + u ^{2}})

分配法則を適用する:

a (b - c) = ab - a c

a = u^{2}, b = 1, c = \frac{u ^{2}}{1 + u ^{2}}

= u^{2} \cdot 1 - u^{2} \frac{u ^{2}}{1 + u ^{2}}

= 1 \cdot u^{2} - \frac{u ^{2}}{1 + u ^{2}} u^{2}

1 \cdot u^{2} = u^{2}

1 \cdot u^{2}

乗算:

1 \cdot u^{2} = u^{2}

= u^{2}

\frac{u ^{2}}{1 + u ^{2}} u^{2} = \frac{u ^{4}}{1 + u ^{2}}

\frac{u ^{2}}{1 + u ^{2}} u^{2}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{u ^{2} u ^{2}}{1 + u ^{2}}

u^{2} u^{2} = u^{4}

u^{2} u^{2}

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u^{2} = u^{2 + 2}

= u^{2 + 2}

数を足す:

2 + 2 = 4

= u^{4}

= \frac{u ^{4}}{1 + u ^{2}}

= u^{2} - \frac{u ^{4}}{u ^{2} + 1}

元を分数に変換する:

u^{2} = \frac{u ^{2} ( 1 + u ^{2} )}{1 + u ^{2}}

= - \frac{u ^{4}}{1 + u ^{2}} + \frac{u ^{2} ( 1 + u ^{2} )}{1 + u ^{2}}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- u ^{4} + u ^{2} ( 1 + u ^{2} )}{1 + u ^{2}}

拡張

- u^{4} + u^{2} (1 + u^{2}) : u^{2}

- u^{4} + u^{2} (1 + u^{2})

拡張

u^{2} (1 + u^{2}) : u^{2} + u^{4}

u^{2} (1 + u^{2})

分配法則を適用する:

a (b + c) = ab + a c

a = u^{2}, b = 1, c = u^{2}

= u^{2} \cdot 1 + u^{2} u^{2}

= 1 \cdot u^{2} + u^{2} u^{2}

簡素化

1 \cdot u^{2} + u^{2} u^{2} : u^{2} + u^{4}

1 \cdot u^{2} + u^{2} u^{2}

1 \cdot u^{2} = u^{2}

1 \cdot u^{2}

乗算:

1 \cdot u^{2} = u^{2}

= u^{2}

u^{2} u^{2} = u^{4}

u^{2} u^{2}

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

u^{2} u^{2} = u^{2 + 2}

= u^{2 + 2}

数を足す:

2 + 2 = 4

= u^{4}

= u^{2} + u^{4}

= u^{2} + u^{4}

= - u^{4} + u^{2} + u^{4}

簡素化

- u^{4} + u^{2} + u^{4} : u^{2}

- u^{4} + u^{2} + u^{4}

条件のようなグループ

= - u^{4} + u^{4} + u^{2}

類似した元を足す:

- u^{4} + u^{4} = 0

= u^{2}

= u^{2}

= \frac{u ^{2}}{1 + u ^{2}}

= \frac{u ^{2}}{1 + u ^{2}}

\frac{u ^{2}}{1 + u ^{2}} = \frac{u ^{2}}{1 + u ^{2}}

\frac{u ^{2}}{1 + u ^{2}} = \frac{u ^{2}}{1 + u ^{2}}

解く

\frac{u ^{2}}{1 + u ^{2}} = \frac{u ^{2}}{1 + u ^{2}} :

すべての

u

で真

\frac{u ^{2}}{1 + u ^{2}} = \frac{u ^{2}}{1 + u ^{2}}

両辺から

\frac{u ^{2}}{1 + u ^{2}}

を引く

\frac{u ^{2}}{1 + u ^{2}} - \frac{u ^{2}}{1 + u ^{2}} = \frac{u ^{2}}{1 + u ^{2}} - \frac{u ^{2}}{1 + u ^{2}}

簡素化

0 = 0

両側は等しい

すべての u で真

すべての u で真

代用を戻す

u = tan (f)

すべての tan (f) で真

すべての tan (f) で真

tan (f) =

すべて真

u \in R : f = arctan (すべて真 u \in R) + πn

tan (f) = すべて真 u \in R

三角関数の逆数プロパティを適用する

tan (f) = すべて真 u \in R

以下の一般解

tan (f) =

すべて真

u \in R

tan (x) = a \Rightarrow x = arctan (a) + πn

f = arctan (すべて真 u \in R) + πn

f = arctan (すべて真 u \in R) + πn

すべての解を組み合わせる

f = arctan (すべて真 u \in R) + πn

equationは以下で未定義のため:

arctan (すべて真 u \in R) + πn

以下の解はない : f \in R

解は

x = \frac{tan ( f )}{1 + tan ^{2} ( f )}

x = \frac{tan ( f )}{1 + tan ^{2} ( f )}

グラフ

人気の例

sin(2x)=((8m-2))/5

sin (2 x) = \frac{( 8 m - 2 )}{5}

csc(3x)=sin(3x)

csc (3 x) = sin (3 x)

sin^2(x)=((10m-7))/9

sin^{2} (x) = \frac{( 10 m - 7 )}{9}

8sin(x)=2+4/(csc(x))

8 sin (x) = 2 + \frac{4}{csc ( x )}

solvefor y,2e^x-sin(y)=x

so l v e f or y, 2 e^{x} - sin (y) = x