cos(θ)=(2sqrt(2))/3

Lösung

cos (θ) = \frac{2 2}{3}

θ = 0.33983 \dots + 2 πn, θ = 2 π - 0.33983 \dots + 2 πn

Grad

θ = 19.47122 \dots^{\circ} + 36 0^{\circ} n, θ = 340.52877 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = \frac{2 2}{3}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = \frac{2 2}{3}

Allgemeine Lösung für

cos (θ) = \frac{2 2}{3}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{2 2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2 2}{3}) + 2 πn

θ = arccos (\frac{2 2}{3}) + 2 πn, θ = 2 π - arccos (\frac{2 2}{3}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 0.33983 \dots + 2 πn, θ = 2 π - 0.33983 \dots + 2 πn

2 cos (x) - 2 sin (x) = - 3

8 cos (2 x) = 8 cos (x) - 9

tan (x) = \frac{2}{1}

so l v e f or x, sin^{2} (x) = \frac{9 m - 8}{2}

cos (θ) = \frac{12}{20}