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受欢迎的三角函数 >

sin(5/2 θ)=-0.966

解答

sin (\frac{5}{2} θ) = - 0.966

解答

θ = - \frac{2 \cdot 1.30928 \dots}{5} + \frac{4 πn}{5}, θ = \frac{2 π}{5} + \frac{2 \cdot 1.30928 \dots}{5} + \frac{4 πn}{5}

+1

度数

θ = - 30.00657 \dots^{\circ} + 14 4^{\circ} n, θ = 102.00657 \dots^{\circ} + 14 4^{\circ} n

求解步骤

sin (\frac{5}{2} θ) = - 0.966

使用反三角函数性质

sin (\frac{5}{2} θ) = - 0.966

sin (\frac{5}{2} θ) = - 0.966

的通解

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

\frac{5}{2} θ = arcsin (- 0.966) + 2 πn, \frac{5}{2} θ = π + arcsin (0.966) + 2 πn

\frac{5}{2} θ = arcsin (- 0.966) + 2 πn, \frac{5}{2} θ = π + arcsin (0.966) + 2 πn

解

\frac{5}{2} θ = arcsin (- 0.966) + 2 πn : θ = - \frac{2 arcsin ( \frac{483}{500} )}{5} + \frac{4 πn}{5}

\frac{5}{2} θ = arcsin (- 0.966) + 2 πn

化简

arcsin (- 0.966) + 2 πn : - arcsin (\frac{483}{500}) + 2 πn

arcsin (- 0.966) + 2 πn

arcsin (- 0.966) = - arcsin (\frac{483}{500})

arcsin (- 0.966)

= arcsin (- \frac{483}{500})

利用以下特性:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{483}{500}) = - arcsin (\frac{483}{500})

= - arcsin (\frac{483}{500})

= - arcsin (\frac{483}{500}) + 2 πn

\frac{5}{2} θ = - arcsin (\frac{483}{500}) + 2 πn

在两边乘以

2

\frac{5}{2} θ = - arcsin (\frac{483}{500}) + 2 πn

在两边乘以

2

2 \cdot \frac{5}{2} θ = - 2 arcsin (\frac{483}{500}) + 2 \cdot 2 πn

化简

2 \cdot \frac{5}{2} θ = - 2 arcsin (\frac{483}{500}) + 2 \cdot 2 πn

化简

2 \cdot \frac{5}{2} θ : 5 θ

2 \cdot \frac{5}{2} θ

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{5 \cdot 2}{2} θ

约分:

2

= θ \cdot 5

化简

- 2 arcsin (\frac{483}{500}) + 2 \cdot 2 πn : - 2 arcsin (\frac{483}{500}) + 4 πn

- 2 arcsin (\frac{483}{500}) + 2 \cdot 2 πn

数字相乘:

2 \cdot 2 = 4

= - 2 arcsin (\frac{483}{500}) + 4 πn

5 θ = - 2 arcsin (\frac{483}{500}) + 4 πn

5 θ = - 2 arcsin (\frac{483}{500}) + 4 πn

5 θ = - 2 arcsin (\frac{483}{500}) + 4 πn

两边除以

5

5 θ = - 2 arcsin (\frac{483}{500}) + 4 πn

两边除以

5

\frac{5 θ}{5} = - \frac{2 arcsin ( \frac{483}{500} )}{5} + \frac{4 πn}{5}

化简

θ = - \frac{2 arcsin ( \frac{483}{500} )}{5} + \frac{4 πn}{5}

θ = - \frac{2 arcsin ( \frac{483}{500} )}{5} + \frac{4 πn}{5}

解

\frac{5}{2} θ = π + arcsin (0.966) + 2 πn : θ = \frac{2 π}{5} + \frac{2 arcsin ( 0.966 )}{5} + \frac{4 πn}{5}

\frac{5}{2} θ = π + arcsin (0.966) + 2 πn

在两边乘以

2

\frac{5}{2} θ = π + arcsin (0.966) + 2 πn

在两边乘以

2

2 \cdot \frac{5}{2} θ = 2 π + 2 arcsin (0.966) + 2 \cdot 2 πn

化简

5 θ = 2 π + 2 arcsin (0.966) + 4 πn

5 θ = 2 π + 2 arcsin (0.966) + 4 πn

两边除以

5

5 θ = 2 π + 2 arcsin (0.966) + 4 πn

两边除以

5

\frac{5 θ}{5} = \frac{2 π}{5} + \frac{2 arcsin ( 0.966 )}{5} + \frac{4 πn}{5}

化简

θ = \frac{2 π}{5} + \frac{2 arcsin ( 0.966 )}{5} + \frac{4 πn}{5}

θ = \frac{2 π}{5} + \frac{2 arcsin ( 0.966 )}{5} + \frac{4 πn}{5}

θ = - \frac{2 arcsin ( \frac{483}{500} )}{5} + \frac{4 πn}{5}, θ = \frac{2 π}{5} + \frac{2 arcsin ( 0.966 )}{5} + \frac{4 πn}{5}

以小数形式表示解

θ = - \frac{2 \cdot 1.30928 \dots}{5} + \frac{4 πn}{5}, θ = \frac{2 π}{5} + \frac{2 \cdot 1.30928 \dots}{5} + \frac{4 πn}{5}

作图

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