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受欢迎的三角函数 >

270=69-tan(45+(x/2))

解答

270 = 69 - tan (4 5^{\circ} + (\frac{x}{2}))

解答

x = - 2 \cdot 1.56582 \dots + 36 0^{\circ} n - 9 0^{\circ}

+1

弧度

x = - 2 \cdot 1.56582 \dots - \frac{π}{2} + 2 πn

求解步骤

270 = 69 - tan (4 5^{\circ} + (\frac{x}{2}))

交换两边

69 - tan (4 5^{\circ} + \frac{x}{2}) = 270

将

69

到右边

69 - tan (4 5^{\circ} + \frac{x}{2}) = 270

两边减去

69

69 - tan (4 5^{\circ} + \frac{x}{2}) - 69 = 270 - 69

化简

- tan (4 5^{\circ} + \frac{x}{2}) = 201

- tan (4 5^{\circ} + \frac{x}{2}) = 201

两边除以

- 1

- tan (4 5^{\circ} + \frac{x}{2}) = 201

两边除以

- 1

\frac{- tan ( 4 5 ^{\circ} + \frac{x}{2} )}{- 1} = \frac{201}{- 1}

化简

tan (4 5^{\circ} + \frac{x}{2}) = - 201

tan (4 5^{\circ} + \frac{x}{2}) = - 201

使用反三角函数性质

tan (4 5^{\circ} + \frac{x}{2}) = - 201

tan (4 5^{\circ} + \frac{x}{2}) = - 201

的通解

tan (x) = - a \Rightarrow x = arctan (- a) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{2} = arctan (- 201) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{2} = arctan (- 201) + 18 0^{\circ} n

解

4 5^{\circ} + \frac{x}{2} = arctan (- 201) + 18 0^{\circ} n : x = - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

4 5^{\circ} + \frac{x}{2} = arctan (- 201) + 18 0^{\circ} n

化简

arctan (- 201) + 18 0^{\circ} n : - arctan (201) + 18 0^{\circ} n

arctan (- 201) + 18 0^{\circ} n

利用以下特性:

arctan (- x) = - arctan (x)

arctan (- 201) = - arctan (201)

= - arctan (201) + 18 0^{\circ} n

4 5^{\circ} + \frac{x}{2} = - arctan (201) + 18 0^{\circ} n

将

4 5^{\circ}

到右边

4 5^{\circ} + \frac{x}{2} = - arctan (201) + 18 0^{\circ} n

两边减去

4 5^{\circ}

4 5^{\circ} + \frac{x}{2} - 4 5^{\circ} = - arctan (201) + 18 0^{\circ} n - 4 5^{\circ}

化简

\frac{x}{2} = - arctan (201) + 18 0^{\circ} n - 4 5^{\circ}

\frac{x}{2} = - arctan (201) + 18 0^{\circ} n - 4 5^{\circ}

在两边乘以

2

\frac{x}{2} = - arctan (201) + 18 0^{\circ} n - 4 5^{\circ}

在两边乘以

2

\frac{2 x}{2} = - 2 arctan (201) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

化简

\frac{2 x}{2} = - 2 arctan (201) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

- 2 arctan (201) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ} : - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

- 2 arctan (201) + 36 0^{\circ} n - 2 \cdot 4 5^{\circ}

2 \cdot 4 5^{\circ} = 9 0^{\circ}

2 \cdot 4 5^{\circ}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 9 0^{\circ}

约分:

2

= 9 0^{\circ}

= - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

x = - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

x = - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

x = - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

x = - 2 arctan (201) + 36 0^{\circ} n - 9 0^{\circ}

以小数形式表示解

x = - 2 \cdot 1.56582 \dots + 36 0^{\circ} n - 9 0^{\circ}

作图

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