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受欢迎的三角函数 >

2/pi arccos(m*1-1)=0

解答

\frac{2}{π} arccos (m \cdot 1 - 1) = 0

解答

m = 2

求解步骤

\frac{2}{π} arccos (m \cdot 1 - 1) = 0

在两边乘以

π

\frac{2}{π} arccos (m 1 - 1) = 0

在两边乘以

π

\frac{2}{π} arccos (m 1 - 1) π = 0 π

化简

2 arccos (m 1 - 1) = 0

2 arccos (m 1 - 1) = 0

两边除以

2

2 arccos (m 1 - 1) = 0

两边除以

2

\frac{2 arccos ( m 1 - 1 )}{2} = \frac{0}{2}

化简

arccos (m 1 - 1) = 0

arccos (m 1 - 1) = 0

使用反三角函数性质

arccos (m \cdot 1 - 1) = 0

arccos (x) = a \Rightarrow x = cos (a)

m \cdot 1 - 1 = cos (0)

cos (0) = 1

cos (0)

使用以下普通恒等式:

cos (0) = 1

cos (0)

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= 1

m \cdot 1 - 1 = 1

m \cdot 1 - 1 = 1

解

m \cdot 1 - 1 = 1 : m = 2

m \cdot 1 - 1 = 1

乘以:

m \cdot 1 = m

m - 1 = 1

将

1

到右边

m - 1 = 1

两边加上

1

m - 1 + 1 = 1 + 1

化简

m = 2

m = 2

m = 2

作图

流行的例子

sin(θ)cos(θ)-1/2 cos(θ)=0

sin (θ) cos (θ) - \frac{1}{2} cos (θ) = 0

cos^2(60)+cos^2(45)+cos^2(x)=1

cos^{2} (60) + cos^{2} (45) + cos^{2} (x) = 1

3sin(5x)=-1,x<2pi,0

3 sin (5 x) = - 1, x < 2 π, 0

3cos(x)+cos(3x)=0

3 cos (x) + cos (3 x) = 0

sin^2(a)=2sin(a)cos(a)

sin^{2} (a) = 2 sin (a) cos (a)