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受欢迎的三角函数 >

sin(x)= pi/4+(0pi)/2

解答

sin (x) = \frac{π}{4} + \frac{0 π}{2}

解答

x = 0.90333 \dots + 2 πn, x = π - 0.90333 \dots + 2 πn

+1

弧度

x = 0.90333 \dots + 6.28318 \dots n, x = π - 0.90333 \dots + 6.28318 \dots n

求解步骤

sin (x) = \frac{π}{4} + \frac{0 π}{2}

化简

\frac{π}{4} + \frac{0 π}{2} : \frac{π}{4}

\frac{π}{4} + \frac{0 π}{2}

\frac{0 π}{2} = 0

\frac{0 π}{2}

使用法则

0 \cdot a = 0

= \frac{0}{2}

使用法则

\frac{0}{a} = 0, a \neq = 0

= 0

= \frac{π}{4} + 0

\frac{π}{4} + 0 = \frac{π}{4}

= \frac{π}{4}

使用反三角函数性质

sin (x) = \frac{π}{4}

sin (x) = \frac{π}{4}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{π}{4}) + 2 πn, x = π - arcsin (\frac{π}{4}) + 2 πn

x = arcsin (\frac{π}{4}) + 2 πn, x = π - arcsin (\frac{π}{4}) + 2 πn

以小数形式表示解

x = 0.90333 \dots + 2 πn, x = π - 0.90333 \dots + 2 πn

作图

流行的例子

cos(2x)-sin(x)-1=0

cos (2 x) - sin (x) - 1 = 0

cos (x) = \frac{5}{20}

sin(x)-sqrt(3)cos(x)=1,0<= x<= 2pi

sin (x) - 3 cos (x) = 1, 0 \leq x \leq 2 π

arccos(θ)= 5/7

arccos (θ) = \frac{5}{7}

cos(θ)=(-139)/(160)

cos (θ) = \frac{- 139}{160}