sin(x)= 1/3 ,sec(y)=(25)/(24,cos(x+y))

解答

sin (x) = \frac{1}{3}, sec (y) = \frac{25}{24 , cos ( x + y )}

x \in R 无解

求解步骤

sin (x) = \frac{1}{3}, sec (y) = \frac{25}{24 , cos ( x + y )}

使用反三角函数性质

sin (x) = \frac{1}{3}

sin (x) = \frac{1}{3}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{1}{3}) + 2 πn, x = π - arcsin (\frac{1}{3}) + 2 πn

x = arcsin (\frac{1}{3}) + 2 πn, x = π - arcsin (\frac{1}{3}) + 2 πn

在

sec (y) = \frac{25}{24 , cos ( x + y )}

范围内的解

x \in R 无解

2 = 2 - π cos (t)

so l v e f or a, 45 = arctanh (\frac{a}{b})

so l v e f or x, sec (x) = 3

cot (θ - 3 0^{\circ}) = \frac{1}{3}

(cot (x) - 3) (csc (x) + 2) = 0