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受欢迎的三角函数 >

(cos(x)=1)=(sec(x)=1)

解答

(cos (x) = 1) = (sec (x) = 1)

解答

x = 2 πn

+1

度数

x = 0^{\circ} + 36 0^{\circ} n

求解步骤

(cos (x) = 1) = (sec (x) = 1)

cos (x) = 1

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

解

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

作图

流行的例子

cot(x/3)=(-1)/(sqrt(3))

cot (\frac{x}{3}) = \frac{- 1}{3}

cos^2(θ)=sin^2(θ)+1,0<= θ<= 360

cos^{2} (θ) = sin^{2} (θ) + 1, 0^{\circ} \leq θ \leq 36 0^{\circ}

tan(2x)(1-tan^2(x))= 2/(sqrt(3))

tan (2 x) (1 - tan^{2} (x)) = \frac{2}{3}

tan (x) = 25762

sin(8x)=sin(6x)

sin (8 x) = sin (6 x)