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受欢迎的三角函数 >

2+cos^2(x)=-5sin(x)

解答

2 + cos^{2} (x) = - 5 sin (x)

解答

x = - 0.57207 \dots + 2 πn, x = π + 0.57207 \dots + 2 πn

+1

度数

x = - 32.77771 \dots^{\circ} + 36 0^{\circ} n, x = 212.77771 \dots^{\circ} + 36 0^{\circ} n

求解步骤

2 + cos^{2} (x) = - 5 sin (x)

两边减去

- 5 sin (x)

2 + cos^{2} (x) + 5 sin (x) = 0

使用三角恒等式改写

2 + cos^{2} (x) + 5 sin (x)

使用毕达哥拉斯恒等式:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= 2 + 1 - sin^{2} (x) + 5 sin (x)

化简

= 5 sin (x) - sin^{2} (x) + 3

3 - sin^{2} (x) + 5 sin (x) = 0

用替代法求解

3 - sin^{2} (x) + 5 sin (x) = 0

令

: sin (x) = u

3 - u^{2} + 5 u = 0

3 - u^{2} + 5 u = 0 : u = - \frac{- 5 + 37}{2}, u = \frac{5 + 37}{2}

3 - u^{2} + 5 u = 0

改写成标准形式

a x^{2} + b x + c = 0

- u^{2} + 5 u + 3 = 0

使用求根公式求解

- u^{2} + 5 u + 3 = 0

二次方程求根公式:

若

a = - 1, b = 5, c = 3

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

u_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 3 = 37

5^{2} - 4 (- 1) \cdot 3

使用法则

- (- a) = a

= 5^{2} + 4 \cdot 1 \cdot 3

数字相乘:

4 \cdot 1 \cdot 3 = 12

= 5^{2} + 12

5^{2} = 25

= 25 + 12

数字相加:

25 + 12 = 37

= 37

u_{1, 2} = \frac{- 5 \pm 37}{2 ( - 1 )}

将解分隔开

u_{1} = \frac{- 5 + 37}{2 ( - 1 )}, u_{2} = \frac{- 5 - 37}{2 ( - 1 )}

u = \frac{- 5 + 37}{2 ( - 1 )} : - \frac{- 5 + 37}{2}

\frac{- 5 + 37}{2 ( - 1 )}

去除括号:

(- a) = - a

= \frac{- 5 + 37}{- 2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 5 + 37}{- 2}

使用分式法则:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{- 5 + 37}{2}

u = \frac{- 5 - 37}{2 ( - 1 )} : \frac{5 + 37}{2}

\frac{- 5 - 37}{2 ( - 1 )}

去除括号:

(- a) = - a

= \frac{- 5 - 37}{- 2 \cdot 1}

数字相乘:

2 \cdot 1 = 2

= \frac{- 5 - 37}{- 2}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

- 5 - 37 = - (5 + 37)

= \frac{5 + 37}{2}

二次方程组的解是:

u = - \frac{- 5 + 37}{2}, u = \frac{5 + 37}{2}

u = sin (x)

代回

sin (x) = - \frac{- 5 + 37}{2}, sin (x) = \frac{5 + 37}{2}

sin (x) = - \frac{- 5 + 37}{2}, sin (x) = \frac{5 + 37}{2}

sin (x) = - \frac{- 5 + 37}{2} : x = arcsin (- \frac{- 5 + 37}{2}) + 2 πn, x = π + arcsin (\frac{- 5 + 37}{2}) + 2 πn

sin (x) = - \frac{- 5 + 37}{2}

使用反三角函数性质

sin (x) = - \frac{- 5 + 37}{2}

sin (x) = - \frac{- 5 + 37}{2}

的通解

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{- 5 + 37}{2}) + 2 πn, x = π + arcsin (\frac{- 5 + 37}{2}) + 2 πn

x = arcsin (- \frac{- 5 + 37}{2}) + 2 πn, x = π + arcsin (\frac{- 5 + 37}{2}) + 2 πn

sin (x) = \frac{5 + 37}{2} :

无解

sin (x) = \frac{5 + 37}{2}

- 1 \leq sin (x) \leq 1

无解

合并所有解

x = arcsin (- \frac{- 5 + 37}{2}) + 2 πn, x = π + arcsin (\frac{- 5 + 37}{2}) + 2 πn

以小数形式表示解

x = - 0.57207 \dots + 2 πn, x = π + 0.57207 \dots + 2 πn

作图

流行的例子

tan^5(x)tan^2(x)=1

tan^{5} (x) tan^{2} (x) = 1

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tan(a)= 5/9 ,b=6

tan (a) = \frac{5}{9}, b = 6

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