(\sqrt[3]{x})^'

Lösung

(3 x)^{^{'}}

\frac{1}{3 x ^{\frac{2}{3}}}

Schritte zur Lösung

(3 x)^{'}

Wende Radikal Regel an:

n a = a^{\frac{1}{n}}

= (x^{\frac{1}{3}})^{^{'}}

Wende die Potenzregel an:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} x^{\frac{1}{3} - 1}

Vereinfache

\frac{1}{3} x^{\frac{1}{3} - 1} : \frac{1}{3 x ^{\frac{2}{3}}}

= \frac{1}{3 x ^{\frac{2}{3}}}

y^{^{''}} - 6 y^{^{'}} + 34 y = 0

\frac{\partial}{\partial x} (\frac{1}{3} x^{3})

\int_{- 1}^{2} (7 - 3 t) d t

s l o p e in t erce pt (- 7, - 3), (- 5, - 8)

t an g e n t 2 - x^{2}