What is the integral of 23e^u ?

The integral of 23e^u is 23e^u+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 23e^u

\int 23 e^{u} d u

23 e^{u} + C

Solution steps

\int 23 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 23 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 23 e^{u}

Add a constant to the solution

= 23 e^{u} + C