What is the integral of x/((2x^2+50)^2) ?

The integral of x/((2x^2+50)^2) is -1/(4(2x^2+50))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of x/((2x^2+50)^2)

\int \frac{x}{( 2 x ^{2} + 50 ) ^{2}} d x

- \frac{1}{4 ( 2 x ^{2} + 50 )} + C

Solution steps

\int \frac{x}{( 2 x ^{2} + 50 ) ^{2}} d x

Apply u-substitution

= \int \frac{1}{4 u ^{2}} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= \frac{1}{4} (- \frac{1}{u})

Substitute back

u = 2 x^{2} + 50

= \frac{1}{4} (- \frac{1}{2 x ^{2} + 50})

Simplify

\frac{1}{4} (- \frac{1}{2 x ^{2} + 50}) : - \frac{1}{4 ( 2 x ^{2} + 50 )}

= - \frac{1}{4 ( 2 x ^{2} + 50 )}

Add a constant to the solution

= - \frac{1}{4 ( 2 x ^{2} + 50 )} + C

What is the integral of x/((2x^2+50)^2) ?
The integral of x/((2x^2+50)^2) is -1/(4(2x^2+50))+C