What is the solution for (dy)/(dx)+y/x = 1/(x^2) ?

The solution for (dy)/(dx)+y/x = 1/(x^2) is y=(ln(x))/x+(c_{1})/x

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(dy)/(dx)+y/x = 1/(x^2)

\frac{d y}{d x} + \frac{y}{x} = \frac{1}{x ^{2}}

y = \frac{ln ( x )}{x} + \frac{c _{1}}{x}

Solution steps

\frac{d y}{d x} + \frac{y}{x} = \frac{1}{x ^{2}}

Solve linear ODE:

y = \frac{ln ( x )}{x} + \frac{c _{1}}{x}

y = \frac{ln ( x )}{x} + \frac{c _{1}}{x}

What is the solution for (dy)/(dx)+y/x = 1/(x^2) ?
The solution for (dy)/(dx)+y/x = 1/(x^2) is y=(ln(x))/x+(c_{1})/x