extreme f(x)=3x^2-6x+9

Lösung

extrempunkte

f (x) = 3 x^{2} - 6 x + 9

Minimum (1, 6)

Schritte zur Lösung

f^{'} (x) = 6 x - 6

Intervalle finden:

Absteigend

: - \infty < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = 1

3 x^{2} - 6 x + 9 : 6

Minimum (1, 6)

e x t re m e Y (s) = \frac{α ^{1}}{s} + \frac{α ^{2}}{2 s + 6}

e x t re m e f (x) = - x^{2} + 4

e x t re m e f (x) = 2 x^{3} - 24 x, - 4 \leq x \leq 4

e x t re m e \frac{1}{4} x^{4} + \frac{1}{2} x^{3} - 3 x^{2} + 8

e x t re m e \frac{1}{4} x^{4} + \frac{1}{2} x^{3} - 3 x^{2} + 2