What is the general solution for 8sin(x)-8=0 ?

The general solution for 8sin(x)-8=0 is x= pi/2+2pin

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8sin(x)-8=0

8 sin (x) - 8 = 0

x = \frac{π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n

Solution steps

8 sin (x) - 8 = 0

Move

8

to the right side

8 sin (x) - 8 = 0

Add

8

to both sides

8 sin (x) - 8 + 8 = 0 + 8

Simplify

8 sin (x) = 8

8 sin (x) = 8

Divide both sides by

8

8 sin (x) = 8

Divide both sides by

8

\frac{8 sin ( x )}{8} = \frac{8}{8}

Simplify

sin (x) = 1

sin (x) = 1

General solutions for

sin (x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{2} + 2 πn

x = \frac{π}{2} + 2 πn

What is the general solution for 8sin(x)-8=0 ?
The general solution for 8sin(x)-8=0 is x= pi/2+2pin