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受欢迎的三角函数 >

-19sin(θ)+19/2 =0

解答

- 19 sin (θ) + \frac{19}{2} = 0

解答

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

+1

度数

θ = 3 0^{\circ} + 36 0^{\circ} n, θ = 15 0^{\circ} + 36 0^{\circ} n

求解步骤

- 19 sin (θ) + \frac{19}{2} = 0

将

\frac{19}{2}

到右边

- 19 sin (θ) + \frac{19}{2} = 0

两边减去

\frac{19}{2}

- 19 sin (θ) + \frac{19}{2} - \frac{19}{2} = 0 - \frac{19}{2}

化简

- 19 sin (θ) = - \frac{19}{2}

- 19 sin (θ) = - \frac{19}{2}

两边除以

- 19

- 19 sin (θ) = - \frac{19}{2}

两边除以

- 19

\frac{- 19 sin ( θ )}{- 19} = \frac{- \frac{19}{2}}{- 19}

化简

\frac{- 19 sin ( θ )}{- 19} = \frac{- \frac{19}{2}}{- 19}

化简

\frac{- 19 sin ( θ )}{- 19} : sin (θ)

\frac{- 19 sin ( θ )}{- 19}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{19 sin ( θ )}{19}

数字相除:

\frac{19}{19} = 1

= sin (θ)

化简

\frac{- \frac{19}{2}}{- 19} : \frac{1}{2}

\frac{- \frac{19}{2}}{- 19}

使用分式法则:

\frac{- a}{- b} = \frac{a}{b}

= \frac{\frac{19}{2}}{19}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{19}{2 \cdot 19}

数字相乘:

2 \cdot 19 = 38

= \frac{19}{38}

约分:

19

= \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

的通解

sin (x)

周期表（周期为

2 πn

"）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

作图

流行的例子

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π cos (π x) + π sin (π x) = 0

144=100+6.93^2-2*10*6.93*cos(x)

144 = 100 + 6.9 3^{2} - 2 \cdot 10 \cdot 6.93 \cdot cos (x)

cos (2 x) = sec (x)

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