Is sec(2x)=(sec^2(x)+sec^4(x))/(2+sec^2(x)-sec^4(x)) ?

The answer to whether sec(2x)=(sec^2(x)+sec^4(x))/(2+sec^2(x)-sec^4(x)) is True

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Popular Trigonometry >

prove sec(2x)=(sec^2(x)+sec^4(x))/(2+sec^2(x)-sec^4(x))

Solution

prove

sec (2 x) = \frac{sec ^{2} ( x ) + sec ^{4} ( x )}{2 + sec ^{2} ( x ) - sec ^{4} ( x )}

Solution

True

Solution steps

sec (2 x) = \frac{sec ^{2} ( x ) + sec ^{4} ( x )}{2 + sec ^{2} ( x ) - sec ^{4} ( x )}

Manipulating right side

\frac{sec ^{2} ( x ) + sec ^{4} ( x )}{2 + sec ^{2} ( x ) - sec ^{4} ( x )}

Express with sin, cos

\frac{sec ^{2} ( x ) + sec ^{4} ( x )}{2 + sec ^{2} ( x ) - sec ^{4} ( x )}

Use the basic trigonometric identity:

sec (x) = \frac{1}{cos ( x )}

= \frac{( \frac{1}{c o s ( x )} ) ^{2} + ( \frac{1}{c o s ( x )} ) ^{4}}{2 + ( \frac{1}{c o s ( x )} ) ^{2} - ( \frac{1}{c o s ( x )} ) ^{4}}

Simplify

\frac{( \frac{1}{c o s ( x )} ) ^{2} + ( \frac{1}{c o s ( x )} ) ^{4}}{2 + ( \frac{1}{c o s ( x )} ) ^{2} - ( \frac{1}{c o s ( x )} ) ^{4}} : \frac{1}{2 cos ^{2} ( x ) - 1}

\frac{( \frac{1}{c o s ( x )} ) ^{2} + ( \frac{1}{c o s ( x )} ) ^{4}}{2 + ( \frac{1}{c o s ( x )} ) ^{2} - ( \frac{1}{c o s ( x )} ) ^{4}}

(\frac{1}{cos ( x )})^{2} = \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{4} = \frac{1}{cos ^{4} ( x )}

(\frac{1}{cos ( x )})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{4}}{cos ^{4} ( x )}

Apply rule

1^{a} = 1

1^{4} = 1

= \frac{1}{cos ^{4} ( x )}

= \frac{( \frac{1}{c o s ( x )} ) ^{2} + ( \frac{1}{c o s ( x )} ) ^{4}}{2 + \frac{1}{c o s ^{2} ( x )} - \frac{1}{c o s ^{4} ( x )}}

(\frac{1}{cos ( x )})^{2} = \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{cos ^{2} ( x )}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{cos ^{2} ( x )}

(\frac{1}{cos ( x )})^{4} = \frac{1}{cos ^{4} ( x )}

(\frac{1}{cos ( x )})^{4}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{4}}{cos ^{4} ( x )}

Apply rule

1^{a} = 1

1^{4} = 1

= \frac{1}{cos ^{4} ( x )}

= \frac{\frac{1}{c o s ^{2} ( x )} + \frac{1}{c o s ^{4} ( x )}}{2 + \frac{1}{c o s ^{2} ( x )} - \frac{1}{c o s ^{4} ( x )}}

Join

2 + \frac{1}{cos ^{2} ( x )} - \frac{1}{cos ^{4} ( x )} : \frac{2 cos ^{4} ( x ) + cos ^{2} ( x ) - 1}{cos ^{4} ( x )}

2 + \frac{1}{cos ^{2} ( x )} - \frac{1}{cos ^{4} ( x )}

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} + \frac{1}{cos ^{2} ( x )} - \frac{1}{cos ^{4} ( x )}

Least Common Multiplier of

1, cos^{2} (x), cos^{4} (x) : cos^{4} (x)

1, cos^{2} (x), cos^{4} (x)

Lowest Common Multiplier (LCM)

Compute an expression comprised of factors that appear in at least one of the factored expressions

= cos^{4} (x)

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

cos^{4} (x)

For

\frac{2}{1} :

multiply the denominator and numerator by

cos^{4} (x)

\frac{2}{1} = \frac{2 cos ^{4} ( x )}{1 \cdot cos ^{4} ( x )} = \frac{2 cos ^{4} ( x )}{cos ^{4} ( x )}

For

\frac{1}{cos ^{2} ( x )} :

multiply the denominator and numerator by

cos^{2} (x)

\frac{1}{cos ^{2} ( x )} = \frac{1 \cdot cos ^{2} ( x )}{cos ^{2} ( x ) cos ^{2} ( x )} = \frac{cos ^{2} ( x )}{cos ^{4} ( x )}

= \frac{2 cos ^{4} ( x )}{cos ^{4} ( x )} + \frac{cos ^{2} ( x )}{cos ^{4} ( x )} - \frac{1}{cos ^{4} ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 cos ^{4} ( x ) + cos ^{2} ( x ) - 1}{cos ^{4} ( x )}

= \frac{\frac{1}{c o s ^{2} ( x )} + \frac{1}{c o s ^{4} ( x )}}{\frac{2 c o s ^{4} ( x ) + c o s ^{2} ( x ) - 1}{c o s ^{4} ( x )}}

Join

\frac{1}{cos ^{2} ( x )} + \frac{1}{cos ^{4} ( x )} : \frac{cos ^{2} ( x ) + 1}{cos ^{4} ( x )}

\frac{1}{cos ^{2} ( x )} + \frac{1}{cos ^{4} ( x )}

Least Common Multiplier of

cos^{2} (x), cos^{4} (x) : cos^{4} (x)

cos^{2} (x), cos^{4} (x)

Lowest Common Multiplier (LCM)

Compute an expression comprised of factors that appear either in

cos^{2} (x)

cos^{4} (x)

= cos^{4} (x)

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

cos^{4} (x)

For

\frac{1}{cos ^{2} ( x )} :

multiply the denominator and numerator by

cos^{2} (x)

\frac{1}{cos ^{2} ( x )} = \frac{1 \cdot cos ^{2} ( x )}{cos ^{2} ( x ) cos ^{2} ( x )} = \frac{cos ^{2} ( x )}{cos ^{4} ( x )}

= \frac{cos ^{2} ( x )}{cos ^{4} ( x )} + \frac{1}{cos ^{4} ( x )}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{cos ^{2} ( x ) + 1}{cos ^{4} ( x )}

= \frac{\frac{c o s ^{2} ( x ) + 1}{c o s ^{4} ( x )}}{\frac{2 c o s ^{4} ( x ) + c o s ^{2} ( x ) - 1}{c o s ^{4} ( x )}}

Divide fractions:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( cos ^{2} ( x ) + 1 ) cos ^{4} ( x )}{cos ^{4} ( x ) ( 2 cos ^{4} ( x ) + cos ^{2} ( x ) - 1 )}

Cancel the common factor:

cos^{4} (x)

= \frac{cos ^{2} ( x ) + 1}{2 cos ^{4} ( x ) + cos ^{2} ( x ) - 1}

Factor

2 cos^{4} (x) + cos^{2} (x) - 1 : (2 cos^{2} (x) - 1) (cos^{2} (x) + 1)

2 cos^{4} (x) + cos^{2} (x) - 1

Let

u = cos^{2} (x)

= 2 u^{2} + u - 1

Factor

2 u^{2} + u - 1 : (2 u - 1) (u + 1)

2 u^{2} + u - 1

Break the expression into groups

2 u^{2} + u - 1

Definition

Factors of

2 : 1, 2

2

Divisors (Factors)

Find the Prime factors of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Add 1

1

The factors of

2

1, 2

Negative factors of

2 : - 1, - 2

Multiply the factors by

- 1

to get the negative factors

- 1, - 2

For every two factors such that

u * v = - 2,

check if

u + v = 1

Check

u = 1, v = - 2 : u * v = - 2, u + v = - 1 \Rightarrow

FalseCheck

u = 2, v = - 1 : u * v = - 2, u + v = 1 \Rightarrow

True

u = 2, v = - 1

Group into

(a x^{2} + ux) + (vx + c)

(2 u^{2} - u) + (2 u - 1)

= (2 u^{2} - u) + (2 u - 1)

Factor out

u

from

2 u^{2} - u : u (2 u - 1)

2 u^{2} - u

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

u^{2} = uu

= 2 uu - u

Factor out common term

u

= u (2 u - 1)

= u (2 u - 1) + (2 u - 1)

Factor out common term

2 u - 1

= (2 u - 1) (u + 1)

= (2 u - 1) (u + 1)

Substitute back

u = cos^{2} (x)

= (cos^{2} (x) + 1) (2 cos^{2} (x) - 1)

= \frac{cos ^{2} ( x ) + 1}{( 2 cos ^{2} ( x ) - 1 ) ( cos ^{2} ( x ) + 1 )}

Cancel the common factor:

cos^{2} (x) + 1

= \frac{1}{2 cos ^{2} ( x ) - 1}

= \frac{1}{2 cos ^{2} ( x ) - 1}

= \frac{1}{- 1 + 2 cos ^{2} ( x )}

Rewrite using trig identities

\frac{1}{- 1 + 2 cos ^{2} ( x )}

Use the Double Angle identity:

2 cos^{2} (x) - 1 = cos (2 x)

= \frac{1}{cos ( 2 x )}

= \frac{1}{cos ( 2 x )}

Rewrite using trig identities

Use the basic trigonometric identity:

cos (x) = \frac{1}{sec ( x )}

\frac{1}{\frac{1}{s e c ( 2 x )}}

Simplify

\frac{1}{\frac{1}{s e c ( 2 x )}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{sec ( 2 x )}{1}

Apply rule

\frac{a}{1} = a

= sec (2 x)

sec (2 x)

sec (2 x)

We showed that the two sides could take the same form

\Rightarrow True

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Frequently Asked Questions (FAQ)

Is sec(2x)=(sec^2(x)+sec^4(x))/(2+sec^2(x)-sec^4(x)) ?
The answer to whether sec(2x)=(sec^2(x)+sec^4(x))/(2+sec^2(x)-sec^4(x)) is True