beweisen tan^2(23)-sec^2(23)=-1

Lösung

beweisen

tan^{2} (2 3^{\circ}) - sec^{2} (2 3^{\circ}) = - 1

Wahr

Schritte zur Lösung

tan^{2} (2 3^{\circ}) - sec^{2} (2 3^{\circ}) = - 1

Verwende die Pythagoreische Identität:

sec^{2} (x) = tan^{2} (x) + 1

sec^{2} (x) - tan^{2} (x) = 1

\Rightarrow Wahr

p ro v e (1 - cos^{2} (t)) (1 + cos^{2} (t)) = 1

p ro v e tan (13 5^{\circ} + a) = \frac{tan ( a ) - 1}{tan ( a ) + 1}

p ro v e (1 - cos^{2} (A)) (1 + cot^{2} (A)) = 1

p ro v e 4 cos^{2} (x) + cos (2 x) = 5 - 6 sin^{2} (x)

p ro v e \frac{sin ^{2} ( 2 x )}{4} = sin^{2} (x) cos^{2} (x)