Is cot^2(x)+csc^2(x)=1+cot^2(x) ?

The answer to whether cot^2(x)+csc^2(x)=1+cot^2(x) is False

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

prove cot^2(x)+csc^2(x)=1+cot^2(x)

prove

cot^{2} (x) + csc^{2} (x) = 1 + cot^{2} (x)

False

Solution steps

cot^{2} (x) + csc^{2} (x) = 1 + cot^{2} (x)

Show that the two sides are not equal

For

cot^{2} (x) + csc^{2} (x) = 1 + cot^{2} (x)

plug in

x = 1

cot^{2} (1) + csc^{2} (1) = 1.82456 \dots

cot^{2} (1) + csc^{2} (1)

Refine to a decimal form

= 1.82456 \dots

1 + cot^{2} (1) = 1.41228 \dots

1 + cot^{2} (1)

Refine to a decimal form

= 1.41228 \dots

The two sides are not equal

\Rightarrow False

Is cot^2(x)+csc^2(x)=1+cot^2(x) ?
The answer to whether cot^2(x)+csc^2(x)=1+cot^2(x) is False