English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Trigonometry >

2sin(2x-30)+1>0

Solution

2 sin (2 x - 30) + 1 > 0

Solution

\frac{180 - π}{12} + πn < x < \frac{7 π + 180}{12} + πn

Interval Notation

(\frac{180 - π}{12} + πn, \frac{7 π + 180}{12} + πn)

Decimal

14.73820 \dots + πn < x < 16.83259 \dots + πn

Solution steps

2 sin (2 x - 30) + 1 > 0

Move

1

to the right side

2 sin (2 x - 30) + 1 > 0

Subtract

1

from both sides

2 sin (2 x - 30) + 1 - 1 > 0 - 1

Simplify

2 sin (2 x - 30) > - 1

2 sin (2 x - 30) > - 1

Divide both sides by

2

2 sin (2 x - 30) > - 1

Divide both sides by

2

\frac{2 sin ( 2 x - 30 )}{2} > \frac{- 1}{2}

Simplify

sin (2 x - 30) > - \frac{1}{2}

sin (2 x - 30) > - \frac{1}{2}

For

sin (x) > a

, if

- 1 \leq a < 1

then

arcsin (a) + 2 πn < x < π - arcsin (a) + 2 πn

arcsin (- \frac{1}{2}) + 2 πn < (2 x - 30) < π - arcsin (- \frac{1}{2}) + 2 πn

a < u < b

then

a < u and u < b

arcsin (- \frac{1}{2}) + 2 πn < 2 x - 30 and 2 x - 30 < π - arcsin (- \frac{1}{2}) + 2 πn

arcsin (- \frac{1}{2}) + 2 πn < 2 x - 30 : x > \frac{180 - π}{12} + πn

arcsin (- \frac{1}{2}) + 2 πn < 2 x - 30

Switch sides

2 x - 30 > arcsin (- \frac{1}{2}) + 2 πn

Simplify

arcsin (- \frac{1}{2}) + 2 πn : - \frac{π}{6} + 2 πn

arcsin (- \frac{1}{2}) + 2 πn

arcsin (- \frac{1}{2}) = - \frac{π}{6}

arcsin (- \frac{1}{2})

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{1}{2}) = - arcsin (\frac{1}{2})

= - arcsin (\frac{1}{2})

Use the following trivial identity:

arcsin (\frac{1}{2}) = \frac{π}{6}

arcsin (\frac{1}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{6}

= - \frac{π}{6}

= - \frac{π}{6} + 2 πn

2 x - 30 > - \frac{π}{6} + 2 πn

Move

30

to the right side

2 x - 30 > - \frac{π}{6} + 2 πn

Add

30

to both sides

2 x - 30 + 30 > - \frac{π}{6} + 2 πn + 30

Simplify

2 x > - \frac{π}{6} + 2 πn + 30

2 x > - \frac{π}{6} + 2 πn + 30

Divide both sides by

2

2 x > - \frac{π}{6} + 2 πn + 30

Divide both sides by

2

\frac{2 x}{2} > - \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2}

Simplify

\frac{2 x}{2} > - \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

- \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2} : 15 + πn - \frac{π}{12}

- \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2}

Group like terms

= \frac{30}{2} + \frac{2 πn}{2} - \frac{\frac{π}{6}}{2}

\frac{30}{2} = 15

\frac{30}{2}

Divide the numbers:

\frac{30}{2} = 15

= 15

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{π}{12}

= 15 + πn - \frac{π}{12}

x > 15 + πn - \frac{π}{12}

x > 15 + πn - \frac{π}{12}

Simplify

15 - \frac{π}{12} : \frac{180 - π}{12}

15 - \frac{π}{12}

Convert element to fraction:

15 = \frac{15 \cdot 12}{12}

= \frac{15 \cdot 12}{12} - \frac{π}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{15 \cdot 12 - π}{12}

Multiply the numbers:

15 \cdot 12 = 180

= \frac{180 - π}{12}

x > \frac{180 - π}{12} + πn

x > \frac{180 - π}{12} + πn

2 x - 30 < π - arcsin (- \frac{1}{2}) + 2 πn : x < \frac{7 π + 180}{12} + πn

2 x - 30 < π - arcsin (- \frac{1}{2}) + 2 πn

Simplify

π - arcsin (- \frac{1}{2}) + 2 πn : π + \frac{π}{6} + 2 πn

π - arcsin (- \frac{1}{2}) + 2 πn

arcsin (- \frac{1}{2}) = - \frac{π}{6}

arcsin (- \frac{1}{2})

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{1}{2}) = - arcsin (\frac{1}{2})

= - arcsin (\frac{1}{2})

Use the following trivial identity:

arcsin (\frac{1}{2}) = \frac{π}{6}

arcsin (\frac{1}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{6}

= - \frac{π}{6}

= π - (- \frac{π}{6}) + 2 πn

Apply rule

- (- a) = a

= π + \frac{π}{6} + 2 πn

2 x - 30 < π + \frac{π}{6} + 2 πn

Move

30

to the right side

2 x - 30 < π + \frac{π}{6} + 2 πn

Add

30

to both sides

2 x - 30 + 30 < π + \frac{π}{6} + 2 πn + 30

Simplify

2 x < π + \frac{π}{6} + 2 πn + 30

2 x < π + \frac{π}{6} + 2 πn + 30

Divide both sides by

2

2 x < π + \frac{π}{6} + 2 πn + 30

Divide both sides by

2

\frac{2 x}{2} < \frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2}

Simplify

\frac{2 x}{2} < \frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2}

Simplify

\frac{2 x}{2} : x

\frac{2 x}{2}

Divide the numbers:

\frac{2}{2} = 1

= x

Simplify

\frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2} : πn + \frac{π}{2} + \frac{π}{12} + 15

\frac{π}{2} + \frac{\frac{π}{6}}{2} + \frac{2 πn}{2} + \frac{30}{2}

Group like terms

= \frac{π}{2} + \frac{30}{2} + \frac{2 πn}{2} + \frac{\frac{π}{6}}{2}

\frac{30}{2} = 15

\frac{30}{2}

Divide the numbers:

\frac{30}{2} = 15

= 15

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Divide the numbers:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{6}}{2} = \frac{π}{12}

\frac{\frac{π}{6}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{6 \cdot 2}

Multiply the numbers:

6 \cdot 2 = 12

= \frac{π}{12}

= \frac{π}{2} + 15 + πn + \frac{π}{12}

Group like terms

= πn + \frac{π}{2} + \frac{π}{12} + 15

x < πn + \frac{π}{2} + \frac{π}{12} + 15

x < πn + \frac{π}{2} + \frac{π}{12} + 15

Simplify

\frac{π}{2} + \frac{π}{12} + 15 : \frac{7 π + 180}{12}

\frac{π}{2} + \frac{π}{12} + 15

Convert element to fraction:

15 = \frac{15}{1}

= \frac{π}{2} + \frac{π}{12} + \frac{15}{1}

Least Common Multiplier of

2, 12, 1 : 12

2, 12, 1

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

12 : 2 \cdot 2 \cdot 3

12

12

divides by

212 = 6 \cdot 2

= 2 \cdot 6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 2 \cdot 3

Prime factorization of

1

Compute a number comprised of factors that appear in at least one of the following:

2, 12, 1

= 2 \cdot 2 \cdot 3

Multiply the numbers:

2 \cdot 2 \cdot 3 = 12

= 12

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

12

For

\frac{π}{2} :

multiply the denominator and numerator by

6

\frac{π}{2} = \frac{π 6}{2 \cdot 6} = \frac{π 6}{12}

For

\frac{15}{1} :

multiply the denominator and numerator by

12

\frac{15}{1} = \frac{15 \cdot 12}{1 \cdot 12} = \frac{180}{12}

= \frac{π 6}{12} + \frac{π}{12} + \frac{180}{12}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π 6 + π + 180}{12}

Add similar elements:

6 π + π = 7 π

= \frac{7 π + 180}{12}

x < \frac{7 π + 180}{12} + πn

x < \frac{7 π + 180}{12} + πn

Combine the intervals

x > \frac{180 - π}{12} + πn and x < \frac{7 π + 180}{12} + πn

Merge Overlapping Intervals

\frac{180 - π}{12} + πn < x < \frac{7 π + 180}{12} + πn

Popular Examples

cos(x)<-1/2

tan^2(x)-3tan(x)+2<0

solvefor x,arctan(|x-y|)>0

cot^2(2t)<0

solvefor x,sin(((x))/(cos(y)))>0